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pochemuha
3 years ago
11

A jewelry maker has 24 jade beads and 30 teak beads. What the the greatest number of necklaces she can make? How many beads of e

ach type are on each necklace?
Mathematics
2 answers:
Darya [45]3 years ago
8 0
Find the GCF of 24 and 30

  24                30
1×24              1×30
2×12             2×15
3×8               3×10
4×6               5×6

The common factors are 1, 2, 3, and 6

That means we can make 6 necklaces, each necklace with 4 jade beads and 5 teak beads. 

-Dominant- [34]3 years ago
3 0
6 necklaces each having 4 jade beads and 5 teak beads
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What is the common denominator of StartFraction 1 Over a EndFraction StartFraction 1 Over b EndFraction in the complex fraction
stepladder [879]

The common denominator is 1

Given the expression:

  • \frac{1/a-1/b}{1/a1/b}

Find the LCM of the numerator to have:

  • \dfrac{\frac{b-a}{ab} }{\frac{1}{a} \frac{1}{b} }

Simplify both the numerator and the denominator to have:

= \dfrac{\frac{b-a}{ab} }{\frac{1}{ab} }\\= \frac{b-a}{ab} \times ab\\=\frac{b-a}{1} \times 1  \\=\frac{b-a}{1}

From the result, we can see that the common denominator is 1

Learn more about fractions here: brainly.com/question/17743912

7 0
3 years ago
Read 2 more answers
Suppose that the population of the scores of all high school seniors who took the SAT Math (SAT-M) test this year follows a Norm
Vlad1618 [11]

Answer:

Confidence =1-\alpha=1-0.01=0.99

And then the confidence level would be given by 99%

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

X \sim N(\mu, \sigma)

The distribution for the sample mean is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\bar x =512 represent the sample mean

\sigma=100 represent the population standard deviation

n= 100 sample size selected.

The confidence interval is given by this formula:

\bar X \pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}   (1)

The marginof error for this case is given by Me=25.76. And we know that the formula for the margin of error is given by:

Me=z_{\alpha/2} \frac{\sigma}{\sqrt{n}}

25.76=z_{\alpha/2} \frac{100}{\sqrt{100}}

And we can find the critical value z_{\alpha/2} like this:

z_{\alpha/2}=\frac{25.76(\sqrt{100})}{100}=2.576

And we know that on the right tail of the z score =2.576 we have \alpha/2 of the total area. We can find the area on the right of the z score using this excel code:

"=1-NORM.DIST(2.576,0,1,TRUE)" or using a table of the normal standard distribution, and we got 0.004998=\alpha/2, so then \alpha=0.00498*2=0.009995 \approx 0.01, and then we can find the confidence like this:

Confidence =1-\alpha=1-0.01=0.99

And then the confidence level would be given by 99%

8 0
3 years ago
Find the measure of the indicated angle.<br> Please can you help?<br> I need to show work.
777dan777 [17]

Answer:

64°

Step-by-step explanation:

∠RQP = 46°

∠PRQ = 180° - 110° = 70°

∠PRQ + ∠RQP + <u>∠RPQ</u> = 180°

70° + 46 + <u>∠RPQ</u> = 180°

116° + <u>∠RPQ</u> = 180°

Find <u>∠RPQ</u>

<u>∠RPQ</u> = 180° - 116° = 64°

4 0
3 years ago
Solve for x: 4(2x − 1) = 2x + 35
PilotLPTM [1.2K]
X = 13/2 or 6 1/2. Hope this helps!
7 0
3 years ago
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A pair of pants normally cost $47.75 and is on sale of 35% off what is the selling price
almond37 [142]

Answer:

$31.04

Step-by-step explanation:

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