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vlabodo [156]
3 years ago
15

Two functions are ________

Mathematics
1 answer:
Reptile [31]3 years ago
7 0

Answer:

always

Step-by-step explanation:

They would always be equivalent if the left side equals the right side no matter what value you place into the variable

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Consider the numbers 4/15 and 3/10 (a) Compare the numbers. (B) find a fraction between the two given numbers
valentinak56 [21]
As a decimal 4/15 = 0.2666667
As a decimal 3/10 = 0.3 [talk about close]
3/10 is bigger.

You could take an average to find something between 4/15 and 3/10
1/2(4/15 + 2/10)
1/2(8/30 + 6/30)
1/2(14/30)
1/2(7/15)
7/30 is between the two given numbers..
5 0
3 years ago
Factorize this term: (a+b)raise to the power of 4 +4
zimovet [89]

Answer:

<u>(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)</u>

Step-by-step explanation:

Given :

  • (a + b)⁴⁺⁴

Solving :

  • (a + b)⁸
  • <u>(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)</u>
8 0
2 years ago
I need help on 19 and 20. Please help me. Please don’t put a link. Please help me.
lianna [129]

Answer:

19:

4  <   third side    <   14  

20:

3  <   third side    <   13  

Step-by-step explanation:

hint: go to http://www.17 28.org/trianinq.htm

(fix the space between 17 and 28)

you're welcome xx

6 0
2 years ago
The general solution to the second-order differential equation y′′+10y=0 is in the form y(x)=c1cosβx+c2sinβx. Find the value of
allsm [11]

Answer:β=√10 or 3.16 (rounded to 2 decimal places)

Step-by-step explanation:

To find the value of β :

  • we will differentiate the y(x) equation twice to get a second order differential equation.
  • We compare our second order differential equation with the Second order differential equation specified in the problem to get the value of β

y(x)=c1cosβx+c2sinβx

we use the derivative of a sum rule to differentiate since we have an addition sign in our equation.

Also when differentiating Cosβx and Sinβx we should note that this involves function of a function. so we will differentiate  βx in each case and multiply with the differential of c1cosx and c2sinx respectively.

lastly the differential of sinx= cosx and for cosx = -sinx.

Knowing all these we can proceed to solving the problem.

y=c1cosβx+c2sinβx

y'= β×c1×-sinβx+β×c2×cosβx  

y'=-c1βsinβx+c2βcosβx

y''=β×-c1β×cosβx + (β×c2β×-sinβx)

y''= -c1β²cosβx -c2β²sinβx

factorize -β²

y''= -β²(c1cosβx +c2sinβx)

y(x)=c1cosβx+c2sinβx

therefore y'' = -β²y

y''+β²y=0

now we compare this with the second order D.E provided in the question

y''+10y=0

this means that β²y=10y

β²=10

B=√10  or 3.16(2 d.p)

5 0
3 years ago
What is n/7 = 3/22 ?
gayaneshka [121]

Answer:

The answer is 21/22

Step-by-step explanation:

n/7=3/22

then you cross-multiply

we have 22n=21

divide both sides by 22 to make n the subject of formula

n=21/22

6 0
3 years ago
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