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3 years ago

Sistemas de ecuaciones no lineales

Mathematics

1 answer:

Rudiy273 years ago

4 0

Answer:

¿que hay de ellos?

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Square root of 5, 0.6, 4/9, 0.7, square root of 2

ella [17]

1: 2.23
2: 0.77
3: 2/3 or 0.6
4: 0.83
5: 1.41

8 0

3 years ago

Plz help on this problem you guys!!!

shutvik [7]

The answer is the 15

3 0

3 years ago

Identify the expression with nonnegative limit values. More info on the pic. PLEASE HELP.

marshall27 [118]

Answer:

$\lim _{x\to 2}\:\frac{x-2}{x^2-2}\\\\ \lim _{x\to 11}\:\frac{x^2+6x-187}{x^2+3x-154}\\\\ \lim _{x\to \frac{5}{2}}\left\frac{2x^2+x-15}{2x-5}\right$

Step-by-step explanation:

a) $\lim _{x\to 3}\:\frac{x^2-10x+21}{x^2+4x-21}=\lim \:_{x\to \:3}\:\frac{\left(x-7\right)\left(x-3\right)}{\left(x+7\right)\left(x-3\right)}=\lim \:_{x\to \:3}\:\frac{x-7}{x+7}=\frac{3-7}{3+7}=-\frac{4}{10}=-\frac{2}{5}$

b) $\lim _{x\to -\frac{3}{2}}\left(\frac{2x^2-5x-12}{2x+3}\right)=\lim \:_{x\to -\frac{3}{2}}\:\frac{\left(2x+3\right)\left(x-4\right)}{\left(2x+3\right)}=\lim \:\:_{x\to \:-\frac{3}{2}}\:\left(x-4\right)=-\frac{3}{2}-4\\ \\ \lim _{x\to -\frac{3}{2}}\left(\frac{2x^2-5x-12}{2x+3}\right)=-\frac{11}{2}$

c) $\lim _{x\to 2}\:\frac{x-2}{x^2-2}=\frac{2-2}{\left(2\right)^2-2}=\frac{0}{4-2}=0$

d) $\lim _{x\to 11}\:\frac{x^2+6x-187}{x^2+3x-154}=\lim _{x\to 11}\:\frac{\left(x-11\right)\left(x+17\right)}{\left(x-11\right)\left(x+14\right)}=\lim _{x\to 11}\:\frac{\left(x+17\right)}{\left(x+14\right)}=\frac{11+17}{11+14}=\frac{28}{25}$

e) $\lim _{x\to 3}\:\frac{x^2-8x+15}{x-3}=\lim \:_{x\to \:3}\:\frac{\left(x-3\right)\left(x-5\right)}{x-3}=\lim _{x\to 3}\left(x-5\right)=3-5=-2$

f) $\lim _{x\to \frac{5}{2}}\left(\frac{2x^2+x-15}{2x-5}\right)=\lim \:_{x\to \:\frac{5}{2}}\frac{\left(2x-5\right)\left(x+3\right)}{2x-5}=\lim \:\:_{x\to \:\:\frac{5}{2}}\left(x+3\right)=\frac{5}{2}+3=\frac{11}{2}$

4 0

2 years ago

Simplify the ratio of 15:24

Anettt [7]

15÷3 and 24÷3

= 5:8
hop u found this helpful

3 0

2 years ago

Read 2 more answers

PLEASE HELP ASAP!!!!

Veseljchak [2.6K]

Answer:

Step-by-step explanation:

R(0,0)

A=((0+2a)/2,(0+2b)/2)=(a,b)

S(2a,2b)

B=((2a+2c)/2,(2b+2d)/2)=(a+c,b+d)

T(2c,2d)

C=((2c+2c)/2,(2d+0)/2)=(2c,d)

V(2c,0)

D=((2c+0)/2,(0+0)/2)=(c,0)

R(0,0)

slope of AB=(b+d-b)/(a+c-a)=d/c

slope of DC=(d-0)/(2c-c)=d/c

slope of AD=(0-b)/(c-a)=-b/(c-a)

slope of BC=(d-b-d)/(2c-a-c)=-b/(c-a)

7 0

3 years ago