Please help? This is due today lol
1 answer:
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The sequence of all odd numbers between 1 and 11 (both inclusive) is
1,3,5,7,9,11
This is an arithmetic sequence with common difference of d=2
The first term is a₁=1.
The number of the term 11 (without counting) is found from
1 + (n-1)*2 = 11
1 + 2n - 2 = 11
2n -1 = 11
2n = 12
n = 6
The sum of the first n terms of an arithmetic sequence is
Therefore, the sum of the sequence is
S₆ = [6*(1 + 11)]/2
= (6*12)/2
= 36
Answer: 36
1,3,5,7,9,11
This is an arithmetic sequence with common difference of d=2
The first term is a₁=1.
The number of the term 11 (without counting) is found from
1 + (n-1)*2 = 11
1 + 2n - 2 = 11
2n -1 = 11
2n = 12
n = 6
The sum of the first n terms of an arithmetic sequence is
Therefore, the sum of the sequence is
S₆ = [6*(1 + 11)]/2
= (6*12)/2
= 36
Answer: 36