Answer:
It isn't possible.
Step-by-step explanation:
Let G be a graph with n vertices. There are n possible degrees: 0,1,...,n-1.
Observe that a graph can not contain a vertice with degree n-1 and a vertice with degree 0 because if one of the vertices has degree n-1 means that this vertice is adjacent to all others vertices, then the other vertices has at least degree 1.
Then there are n vertices and n-1 possible degrees. By the pigeon principle there are two vertices that have the same degree.
The triangles are similar by SAS principle.
<h3>How to know similar triangles?</h3>
Similar triangles have the same shape but may have different sizes.
In similar triangles, corresponding sides are always in the same ratio.
The corresponding angles are congruent.
Therefore, using SAS ratio,
6 / 8 = 8 × 3 / 32
6 / 8 = 24 / 32 = 3 / 4
Therefore, the corresponding sides are a ratio of each other.
Therefore, the triangles are similar by SAS principles because the two triangles have two pairs of sides in the same ratio and the included angles are also equal
learn more on similar triangle here: brainly.com/question/21480885
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Answer:
Option B 13 units is correct.
Step-by-step explanation:
The formula used to find distance between 2 points is:
x₁ = 12 x₂ = 0 y₁= 9 and y₂=4
Putting values in the formula:
So, Option B 13 units is correct.
Answer:
1. x=y−2
2. -1/2y + 4
Step-by-step explanation:
Answer:
Step-by-step explanation:
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
The population proportion have the following distribution
And we can solve the problem using the z score on this case given by:
We are interested on this probability:
And we can use the z score formula, and we got this:
And we can find this probability like this:
