11
(9, 18, 27, 36, 45, 54, 63, 72, 81, 90 and 99)
Those numbers divisible by 9 are the multiple of 9; thus need to know how many multiples of 9 there are between 1 and 100:
100 ÷ 9 = 11 r 1 ÷ last multiple of 9 is 11 × 9 (= 99)
→ There are 11 - 1 + 1 = 11 numbers between 1 and 100 which are divisible by 9.
(They are 9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99.)
Answer:
6
Step-by-step explanation:
if you do the ratio 9/12 and 3/x and cross multiply, x=6... I believe
Because
Answer:
Solution given:
Since the given triangle is isosceles and right angled triangle
perpendicular [p]=base[b]=x
hypotenuse [h]=6
we have
by using Pythagoras law
p²+b²=h²
x²+x²=6²
2x²=36
x²=36/2
x²=18
x=
<u>x</u>=
Answer: FBE
Step-by-step explanation:
EDGE
Answer:
x=6
Step-by-step explanation:
5x+2=32
Step 1: Subtract 2 from both sides.
5x+2−2=32−2
5x=30
Step 2: Divide both sides by 5.
5x
5
=
30
5
x=6
