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earnstyle [38]
3 years ago
5

There were two trees growing seeds in a backyard. One tree grew at a rate of 1/2 a foot every 2 years. The other grew 4 inches e

very 3 years. In 12 years, what will the difference between the heights of the two trees be in inches?? Plzz I will give you 299 points
Mathematics
1 answer:
denis-greek [22]3 years ago
7 0

Answer:

20 in  

Step-by-step explanation:

Tree 1:

Rate of growth = (½ ft/2 yr)

  12 yr growth = 12 × (½/2)

                       = 6/2

                       = 3 ft

                       = 36 in

Tree 2:

Rate of growth = (4 in/3yr)

  12 yr growth = 12 × (4/3)

                       = 48/3

                       = 16 in

Difference:

Tree 1 - Tree 2 = 36 - 16

                            = 20 in

The trees will differ in height by 20 in.

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A doctor estimates that a particular patient is losing bone density at a rate of 3% annually. The patient currently has a bone d
kompoz [17]

Answer:

The function f(x) is represented by:

f(x)=1500(0.97)^x

Hence, a=1500 and b=0.97

Step-by-step explanation:

The patient currently has a bone density of 1,500 kg/mg^3.

A doctor estimates that a particular patient is losing bone density at a rate of 3% annually.

This means that the bone density that is remaining is:

100-3=97%

which is also represented as: 97%=97/100=0.97

Hence, the function f(x) that represents the bone density after x years is represented by:

f(x)=a(0.97)^x

where a is the initial bone density which is given to be: 1500 kg/mg^3.

Hence, the function is:

f(x)=1500(0.97)^x

6 0
3 years ago
Read 2 more answers
Strain-displacement relationship) Consider a unit cube of a solid occupying the region 0 ≤ x ≤ 1, 0 ≤ y ≤ 1, 0 ≤ z ≤ 1 After loa
Anastasy [175]

Answer:

please see answers are as in the explanation.

Step-by-step explanation:

As from the data of complete question,

0\leq x\leq 1\\0\leq y\leq 1\\0\leq z\leq 1\\u= \alpha x\\v=\beta y\\w=0

The question also has 3 parts given as

<em>Part a: Sketch the deformed shape for α=0.03, β=-0.01 .</em>

Solution

As w is 0 so the deflection is only in the x and y plane and thus can be sketched in xy plane.

the new points are calculated as follows

Point A(x=0,y=0)

Point A'(x+<em>α</em><em>x,y+</em><em>β</em><em>y) </em>

Point A'(0+<em>(0.03)</em><em>(0),0+</em><em>(-0.01)</em><em>(0))</em>

Point A'(0<em>,0)</em>

Point B(x=1,y=0)

Point B'(x+<em>α</em><em>x,y+</em><em>β</em><em>y) </em>

Point B'(1+<em>(0.03)</em><em>(1),0+</em><em>(-0.01)</em><em>(0))</em>

Point <em>B</em>'(1.03<em>,0)</em>

Point C(x=1,y=1)

Point C'(x+<em>α</em><em>x,y+</em><em>β</em><em>y) </em>

Point C'(1+<em>(0.03)</em><em>(1),1+</em><em>(-0.01)</em><em>(1))</em>

Point <em>C</em>'(1.03<em>,0.99)</em>

Point D(x=0,y=1)

Point D'(x+<em>α</em><em>x,y+</em><em>β</em><em>y) </em>

Point D'(0+<em>(0.03)</em><em>(0),1+</em><em>(-0.01)</em><em>(1))</em>

Point <em>D</em>'(0<em>,0.99)</em>

So the new points are A'(0,0), B'(1.03,0), C'(1.03,0.99) and D'(0,0.99)

The plot is attached with the solution.

<em>Part b: Calculate the six strain components.</em>

Solution

Normal Strain Components

                             \epsilon_{xx}=\frac{\partial u}{\partial x}=\frac{\partial (\alpha x)}{\partial x}=\alpha =0.03\\\epsilon_{yy}=\frac{\partial v}{\partial y}=\frac{\partial ( \beta y)}{\partial y}=\beta =-0.01\\\epsilon_{zz}=\frac{\partial w}{\partial z}=\frac{\partial (0)}{\partial z}=0\\

Shear Strain Components

                             \gamma_{xy}=\gamma_{yx}=\frac{\partial u}{\partial y}+\frac{\partial v}{\partial x}=0\\\gamma_{xz}=\gamma_{zx}=\frac{\partial u}{\partial z}+\frac{\partial w}{\partial x}=0\\\gamma_{yz}=\gamma_{zy}=\frac{\partial w}{\partial y}+\frac{\partial v}{\partial z}=0

Part c: <em>Find the volume change</em>

<em></em>\Delta V=(1.03 \times 0.99 \times 1)-(1 \times 1 \times 1)\\\Delta V=(1.0197)-(1)\\\Delta V=0.0197\\<em></em>

<em>Also the change in volume is 0.0197</em>

For the unit cube, the change in terms of strains is given as

             \Delta V={V_0}[(1+\epsilon_{xx})]\times[(1+\epsilon_{yy})]\times [(1+\epsilon_{zz})]-[1 \times 1 \times 1]\\\Delta V={V_0}[1+\epsilon_{xx}+\epsilon_{yy}+\epsilon_{zz}+\epsilon_{xx}\epsilon_{yy}+\epsilon_{xx}\epsilon_{zz}+\epsilon_{yy}\epsilon_{zz}+\epsilon_{xx}\epsilon_{yy}\epsilon_{zz}-1]\\\Delta V={V_0}[\epsilon_{xx}+\epsilon_{yy}+\epsilon_{zz}]\\

As the strain values are small second and higher order values are ignored so

                                      \Delta V\approx {V_0}[\epsilon_{xx}+\epsilon_{yy}+\epsilon_{zz}]\\ \Delta V\approx [\epsilon_{xx}+\epsilon_{yy}+\epsilon_{zz}]\\

As the initial volume of cube is unitary so this result can be proved.

5 0
2 years ago
The formula to find the perimeter of a rectangle is: P = 2W + 2L. To solve for " W " in this formula, which steps should be foll
netineya [11]
Since the 2L is not being multiplied or divided, and it's positive, we will subtract it from both sides. Since the W is being multiplied by the 2, we'll also need to divide both sides by 2. 

Your answer is B.
<em>
</em><em>Don't forget to rate this answer the Brainliest!</em>

3 0
2 years ago
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Which inequality is true
Elodia [21]
The answer is 3 your welcome
5 0
3 years ago
Read 2 more answers
$800 principal earning 7%, compounded annually, after 4 years
Jlenok [28]

Answer:

$1050

Step-by-step explanation:

<h2><u>formula for compound interest method:</u></h2>

A = P ( 1 + r/100)^n

A is actual amount

r is the rate of interest

P is the principle

n is the number of years

A = 800 (1 * 7/100)^4

= 1048.637

to 3sf = <u>$1050</u>

6 0
3 years ago
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