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Veronika [31]
4 years ago
13

Camille asked five of her friends how long they studied for the last math test and what grade they received. She found a linear

regression equation for the data to be y = 9.6x + 65.8, with x representing hours.
What does the 9.6 and the 65.8 mean in the context of this equation?
A) 9.6 = the lowest score you can get;
65.8 = the highest score you can get
B) 9.6 = the number of points you would increase each hour of studying;
65.8 = your score if you studied 0 hours
C) 9.6 = the number of points you would increase each hour of studying;
65.8 = the highest score you can get
D) 9.6 = the number of hours you studied;
65.8 = your score if you studied 0 hours
Mathematics
1 answer:
Gala2k [10]4 years ago
6 0

Answer:

B. 9.6 = the number of points you would increase each hour of studying;

65.8 = your score if you studied 0 hours

Step-by-step explanation:

A linear regression equation y = 9.6x + 65.8, with x representing hours.

When x = 0, then y = 65.8. This means

65.8 = your score if you studied 0 hours

When x = 1, then

y=9.6+65.8=75.4

is your score after studying one hour.

The score increased by 75.4-65.8=9.6, so

9.6 = the number of points you would increase each hour of studying.

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Write the given second order equation as its equivalent system of first order equations. u′′−5u′−4u=1.5sin(3t),u(1)=1,u′(1)=2.5
lakkis [162]

Answer:

hi your question options is not available but attached to the answer is a complete question with the question options that you seek answer to

Answer:  v = 5v + 4u + 1.5sin(3t),

  • 0
  • 1
  •  4
  • 5
  • 0
  • 1.5sin(3t)
  • 1
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Step-by-step explanation:

u" - 5u' - 4u = 1.5sin(3t)        where u'(1) = 2.5   u(1) = 1

v represents the "velocity function"   i.e   v = u'(t)

As v = u'(t)

<em>u' = v</em>

since <em>u' = v </em>

v' = u"

v'  = 5u' + 4u + 1.5sin(3t)   ( given that u" - 5u' - 4u = 1.5sin(3t) )

    = 5v + 4u + 1.5sin(3t)  ( noting that v = u' )

so v' = 5v + 4u + 1.5sin(3t)

d/dt \left[\begin{array}{ccc}u&\\v&\\\end{array}\right]= \left[\begin{array}{ccc}0&1&\\4&5&\\\end{array}\right]  \left[\begin{array}{ccc}u&\\v&\\\end{array}\right] + \left[\begin{array}{ccc}0&\\1.5sin(3t)&\\\end{array}\right]

Given that u(1) = 1 and u'(1) = 2.5

since v = u'

v(1) = 2.5

note: the initial value for the vector valued function is given as

\left[\begin{array}{ccc}u(1)&\\v(1)\\\end{array}\right]  = \left[\begin{array}{ccc}1\\2.5\\\end{array}\right]

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Step-by-step explanation: all you have to do is add the sides. 5+5=10

4+4= 8

10+8=18

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