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BartSMP [9]
3 years ago
8

Which type of function is the result of multiplying a quadratic function and a linear function?

Mathematics
1 answer:
yawa3891 [41]3 years ago
4 0

Answer:

A cubic function

Step-by-step explanation:

When you multiply powers of a same base, the exponents sum. So, if we multiply a function like ax^2+bx+c with a function like dx+e we get

(ax^2+bx+c)(dx+e) = adx^3+bdx^2+cdx+aex^2+bex+ce = adx^3+(bd+ae)x^2+(cd+be)x+ce

which is a cubic function, because it is written in the form

\alpha x^3+\beta x^3 + \gamma x + \delta

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Write the equation of the line that passes through the points (2,0) and (1,-2)
Darya [45]

Answer:

y

=

2

x

−

1

Explanation:

First, we need to determine the slope of the line. The formula for determining the slope of a line is:

m

=

y

2

−

y

1

x

2

−

x

1

where

m

is the slope and the x and y terms are for the points:

(

x

1

,

y

1

)

and

(

x

2

,

y

2

)

For this problem the slope is:

m

=

3

−

−

1

2

−

0

m

=

3

+

1

2

m

=

4

2

m

=

2

Now, selecting one of the points we can use the point slope formula to find the equation.

The point slope formula is:

y

−

y

1

=

m

(

x

−

x

1

)

Substituting one of our points gives:

y

−

−

1

=

2

(

x

−

0

)

y

+

1

=

2

x

Solving for

y

to put this in standard form gives:

y

+

1

−

1

=

2

x

−

1

y

+

0

=

2

x

−

1

y

=

2

x

−

1

Answer linky

=

2

x

−

1

Explanation:

First, we need to determine the slope of the line. The formula for determining the slope of a line is:

m

=

y

2

−

y

1

x

2

−

x

1

where

m

is the slope and the x and y terms are for the points:

(

x

1

,

y

1

)

and

(

x

2

,

y

2

)

For this problem the slope is:

m

=

3

−

−

1

2

−

0

m

=

3

+

1

2

m

=

4

2

m

=

2

Now, selecting one of the points we can use the point slope formula to find the equation.

The point slope formula is:

y

−

y

1

=

m

(

x

−

x

1

)

Substituting one of our points gives:

y

−

−

1

=

2

(

x

−

0

)

y

+

1

=

2

x

Solving for

y

to put this in standard form gives:

y

+

1

−

1

=

2

x

−

1

y

+

0

=

2

x

−

1

y

=

2

x

−

1

Answer link

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2 years ago
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