Procedure:
1) calculate the number of diferent teams of four members that can be formed (with the ten persons)
2) calculate the number of teams tha meet the specification (two girls and two boys)
3) Divide the positive events by the total number of events: this is the result of 2) by the result in 1)
Solution
1) the number of teams of four members that can be formed are:
10*9*8*7 / (4*3*2*1) = 210
2) Number of different teams with 2 boys and 2 girls = ways of chosing 2 boys * ways of chosing 2 girls
Ways of chosing 2 boys = 6*5/2 = 15
Ways of chosing 2 girls = 4*3/2 = 6
Number of different teams with 2 boys and 2 girls = 15 * 6 = 90
3) probability of choosing one of the 90 teams formed by 2 boys and 2 girls:
90/210 = 3/7
Answer: the price for an adult ticket is $3
Step-by-step explanation:
Let x represent the price of one adult ticket.
Let y represent the price of one child ticket.
The Martinez family went to play and paid $13 for 1 adult and 4 children. This means that
x + 4y = 13 - - - - - - - - - - -1
The Hernandez family went to the same place and paid $14 for 3 adults and 2 children. This means that
3x + 2y = 14 - - - -- - - - - - - -2
Multiplying equation 1 by 3 and equation 3 by 1, it becomes
3x + 12y = 39
3x + 2y = 14
Subtracting, it becomes
10y = 25
y = 25/10 = 2.5
Substituting y = 2.5 into equation 1, it becomes
x + 4 × 2.5 = 13
x + 10 = 13
x = 13 - 10
x = 3
Answer:
c = 2 *pie* r
Step-by-step explanation:
