Answer:
3
+ 11a³ - 7a² + 18a - 18
Step-by-step explanation:
<u>When multiplying with two brackets, you need to multiply the three terms, (a²), (4a) and (-6) from the first bracket to all the terms in the second brackets, (3a²), (-a) and (3) individually. I have put each multiplied term in a bracket so it is easier.</u>
(a² + 4a - 6) × (3a² - a + 3) =
(a² × <em>3a²</em>) + {a² × <em>(-a)</em>} + (a² × <em>3</em>) + (4a × <em>3a²</em>) + {4a × <em>(-a)</em>} + (4a × <em>3</em>) + {(-6) × <em>a²</em>) + {(-6) × <em>(-a)</em>} + {(-6) × <em>3</em>}
<u>Now we can evaluate the terms in the brackets. </u>
(a² × 3a²) + {a² × (-a)} + (a² × 3) + (4a × 3a²) + {4a × (-a)} + (4a × 3) + {(-6) × a²) + {(-6) × (-a)} + {(-6) × 3} =
3 + (-a³) + 3a² + 12a³ + (-4a²) + 12a + (-6a²) + 6a + (-18)
<u>We can open the brackets now. One plus and one minus makes a minus. </u>
3 + (-a³) + 3a² + 12a³ + (-4a²) + 12a + (-6a²) + 6a + (-18) =
3 -a³ + 3a² + 12a³ -4a² + 12a -6a² + 6a -18
<u>Evaluate like terms.</u>
3 -a³ + 3a² + 12a³ -4a² + 12a -6a² + 6a -18 = 3 + 11a³ - 7a² + 18a - 18
What should denise do for her next step?
Answer: Out of all the options presented above the one that best represents the next step that denise should take after already using her straightedge and compass to construct the circle, lines, and arcs is to use the straightedge to draw line ac, line ad, line bc, and line bd. use the compass and straightedge to construct the bisector of ∠cpb∠cpb. Please see the attachment as reference to how it should look like once it is completed.
I hope it helps, Regards.
Answer: B
Step-by-step explanation:
The domain of a function is the set of x-values.
Answer:
alright
Step-by-step explanation:
(f+g)(x) = f(x) + g(x) = (|x| + 9 ) + (-6) =
|x| + 9 - 6 = |x| + 3
Answer is |x| + 3
