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Firdavs [7]
3 years ago
5

What are the vertex and x-intercepts of the graph of the function given below?

Mathematics
2 answers:
Travka [436]3 years ago
7 0
In order to determine the vertex of this, you can complete the square.  To do that, first set the equation equal to 0, then move the -35 over to the other side by adding.  That gives us x^{2} -2x=35.  Now we can complete the square.  Do this by taking half of the linear term, squaring it, and adding it in to both sides.  Our linear term is 2x.  Half of 2 is 1, and 1 squared is 1.  So we add 1 to both sides, creating something that looks like this: x^{2} -2x+1=35+1.  We will do the math on the right and get 36, and the left will be expressed as the perfect square binomial we created by doing this whole process.  (x-1)^2=36.  Now move the 36 over by subtraction and set it back to equal y and your vertex is apparent.  It is (1, -36).  You find the x-intercepts when y = 0.  That means you need to set your original equation equal to zero and factor it.  The easiest, surest way to do this is to use the quadratic formula.  Doing that gives us x values of 7 and -5.  And you're done!
NARA [144]3 years ago
7 0

Answer:D

Step-by-step explanation:I got the answer right :)

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HELPP!!
Tamiku [17]

Answer:

$1,562.50

Step-by-step explanation:

Markup= (selling price- cost)/cost

Let cost be represented by  C

0.20 = (1875-C)/ C

0.20C = 1875 - C

0.20C+ C = 1875

1.20C=1875

Divide both sides by 1.20;

C= 1875/1.20

C= $1,562.50

The wholesale cost was $1,562.50

4 0
3 years ago
Determine as a linear relation in x, y, z the plane given by the vector function F(u, v) = a + u b + v c when a = 2 i − 2 j + k,
Ostrovityanka [42]

Answer:

2x - y - 3z = 0

Step-by-step explanation:

Since the set

{i, j}  = {(1,0), (0,1)}

is a base in \mathbb{R}^2

and F is linear, then

<em>{F(1,0), F(0,1)}  </em>

would be a base of the plane generated by F.

F(1,0) = a+b = (2i-2j+k)+(i+2j+k) = 3i+2k

F(0,1) = a+c = (2i-2j+k)+(2i+j+2k) = 4i-j+3k

Now, we just have to find the equation of the plane that contains the vectors 3i+2k and 4i-j+3k

We need a normal vector which is the cross product of 3i+2k and 4i-j+3k

(3i+2k)X(4i-j+3k) = 2i-j-3k

The equation of the plane whose normal vector is 2i-j-3k and contains the point (3,0,2) (the end of the vector F(1,0)) is given by

2(x-3) -1(y-0) -3(z-2) = 0

or what is the same

2x - y - 3z = 0

3 0
3 years ago
What is |-3|+|-2|? Please answer asap! Thank you
makvit [3.9K]
A - 24!

-21 as its true value is 21

-3 as its true value is 3

if you add them together you get 24!

Hope this helped ^^
5 0
3 years ago
Read 2 more answers
A bakery wants to determine how many trays of doughnuts it should prepare each day. Demand is normal with a mean of 5 trays and
Alexeev081 [22]

Answer:

4 trays should he prepared, if the owner wants a service level of at least 95%.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 5

Standard Deviation, σ = 1

We are given that the distribution of demand score is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(X > x) = 0.95

We have to find the value of x such that the probability is 0.95

P(X > x)  

P( X > x) = P( z > \displaystyle\frac{x - 5}{1})=0.95  

= 1 -P( z \leq \displaystyle\frac{x - 5}{1})=0.95  

=P( z \leq \displaystyle\frac{x - 5}{1})=0.05  

Calculation the value from standard normal z table, we have,  

\displaystyle\frac{x - 5}{1} = -1.645\\x = 3.355 \approx 4  

Hence,  4 trays should he prepared, if the owner wants a service level of at least 95%.

3 0
3 years ago
Which figure shows that
FromTheMoon [43]
It’s either Option 1 or 4
7 0
3 years ago
Read 2 more answers
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