Answer:
Check the explanation
Explanation:
<em>Cube.m:</em>
mass = input("Enter the mass of cube [kilograms]: ");
if(mass<=0)
disp("Error: Mass must be greater than zero grams")
else
fprintf("The length of one side of cube is %.2f inches",2.7*mass);
end
<em>Output1</em>
octave:2> source ( Cube.m Enter the mass of cube [kilograms]: octave:2>-3 Error: Mass must be greater than zero grams
<em />
Answer:
public class MagicSquare {
public static void main(String[] args) {
int[][] square = {
{ 8, 11, 14, 1},
{13, 2, 7,12},
{ 3, 16, 9, 6},
{10, 5, 4, 15}
};
System.out.printf("The square %s a magic square. %n",
(isMagicSquare(square) ? "is" : "is not"));
}
public static boolean isMagicSquare(int[][] square) {
if(square.length != square[0].length) {
return false;
}
int sum = 0;
for(int i = 0; i < square[0].length; ++i) {
sum += square[0][i];
}
int d1 = 0, d2 = 0;
for(int i = 0; i < square.length; ++i) {
int row_sum = 0;
int col_sum = 0;
for(int j = 0; j < square[0].length; ++j) {
if(i == j) {
d1 += square[i][j];
}
if(j == square.length-i-1) {
d2 += square[i][j];
}
row_sum += square[i][j];
col_sum += square[j][i];
}
if(row_sum != sum || col_sum != sum) {
return false;
}
}
return d1 == sum && d2 == sum;
}
}
To get the network number and node number of the destination machine. The subnet mask is usually called the NETwork MASK, so anding it with the address gives you the network number. Using the not logical operator on the netmask then protects the node bits in a second and operation.
address & netmask = network number
address & not( netmask ) = node number
The not operator essentially just flips the bits of it's argument.
Answer:
একটি ছবির মূল্য 84.1 শব্দের
Explanation:
Answer:
Try going to your settings and allow output camera
Explanation:
