Answer:
your on unit 9 of edhesive?
Explanation:
C. schedule.
Outlook adds your appointment to your schedule folder.
Yes , it’s true. In a known-plaintext attack (kpa), the cryptanalyst can only view a small portion of encrypted data, and he or she has no control over what that data might be.
The attacker also has access to one or more pairs of plaintext/ciphertext in a Known Plaintext Attack (KPA). Specifically, consider the scenario where key and plaintext were used to derive the ciphertext (either of which the attacker is trying to find). The attacker is also aware of what are the locations of the output from key encrypting. That is, the assailant is aware of a pair. They might be familiar with further pairings (obtained with the same key).
A straightforward illustration would be if the unencrypted messages had a set expiration date after which they would become publicly available. such as the location of a planned public event. The coordinates are encrypted and kept secret prior to the event. But when the incident occurs, the attacker has discovered the value of the coordinates /plaintext while the coordinates were decrypted (without knowing the key).
In general, a cipher is easier to break the more plaintext/ciphertext pairs that are known.
To learn more about Plaintext Attack click here:
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The result of the subtraction of 4365 and 3412 using octal numbers is of:
753.
<h3>What are octal numbers?</h3>
For octal numbers, each number is represented by three bits, as follows:
Then the binary representation of number 4365 is given as follows:
100011110101
The binary representation of number 3412 is given as follows:
011100001010
Then the following binary subtraction is made:
100011110101 - 011100001010
The result of this subtraction is of:
100011110101 - 011100001010 = 111101011
Then the octal result is given as follows:
111 101 011 = 753.
More can be learned about binary numbers at brainly.com/question/8649831
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