Answer: Choice C)
We start at 0 and move 1.4 units to the right. Then we move another 2.3 units to the right to land on 3.7
Notice how 1.4 - (-2.3) = 1.4 + 2.3 = 3.7
Answer: circumference
Step-by-step explanation: you’re welcome
let's first off, convert the mixed fractions to improper fractions, and then, let's multiply both sides by the LCD, notice, the LCD will be hmmmm 4, so we'll multiply both sides by 4, to do away with the denominators.
![\bf \stackrel{mixed}{3\frac{1}{2}}\implies \cfrac{3\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{7}{2}}~\hfill \stackrel{mixed}{3\frac{1}{4}}\implies \cfrac{3\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{13}{4}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{7}{2}w+8=\cfrac{13}{4}w+10\implies \stackrel{\textit{multiplying by }\stackrel{LCD}{4}}{4\left( \cfrac{7}{2}w+8 \right)=4\left( \cfrac{13}{4}w+10 \right)} \\\\\\ 14w+32=13w+40\implies w=40-32\implies \boxed{w=8}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B3%5Cfrac%7B1%7D%7B2%7D%7D%5Cimplies%20%5Ccfrac%7B3%5Ccdot%202%2B1%7D%7B2%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B7%7D%7B2%7D%7D~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B3%5Cfrac%7B1%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B3%5Ccdot%204%2B1%7D%7B4%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B13%7D%7B4%7D%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A%5Ccfrac%7B7%7D%7B2%7Dw%2B8%3D%5Ccfrac%7B13%7D%7B4%7Dw%2B10%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bmultiplying%20by%20%7D%5Cstackrel%7BLCD%7D%7B4%7D%7D%7B4%5Cleft%28%20%5Ccfrac%7B7%7D%7B2%7Dw%2B8%20%5Cright%29%3D4%5Cleft%28%20%5Ccfrac%7B13%7D%7B4%7Dw%2B10%20%5Cright%29%7D%0A%5C%5C%5C%5C%5C%5C%0A14w%2B32%3D13w%2B40%5Cimplies%20w%3D40-32%5Cimplies%20%5Cboxed%7Bw%3D8%7D)
Answer:
x = 16
Step-by-step explanation:
(whole secant) x (external part) = (tangent)^2
(x+2) * 2 = 6^2
2(x+2) = 36
Divide each side by 2
x+2 = 18
Subtract 2
x+2-2 = 18-2
x = 16
Ten plus eight teen plus eight
Thirty six
Ten times ten
One hundred
One hundred minus thirty six
Sixty four
1/64 is the fraction and the answer