Ask question

Ask question

All categories

3 years ago

13

a bag containes 8 white marbels and 48 green marbles. If a representative sample contains 2 white marblesthen how many green mar

bles would you expect it to contain?

1 answer:

aliya0001 [1]3 years ago

5 0

Answer:

12

Step-by-step explanation:

8 white marbles and 48 marbles

each sample contains 2 white

so first

8 divide 2 = 4

then second

48 divide 4= 12

hope this helps

You might be interested in

;-; hehehehehehehehehe

iogann1982 [59]

Answer: hahahahahaha

Step-by-step explanation:

Hahahahaha mines more cringe ;)

8 0

3 years ago

Read 2 more answers

Substitution method 2x-y+24 y=-3x+16

Llana [10]

- Using substitution means you are going to solve one equation for one variable and substitute with its value in the other equation in order to get also an equation with one variable.

4 0

3 years ago

Describe the discontinutiy for the function f(x)= x^2+5/x-5

coldgirl [10]

Answer:

f(x) = x² + 5 / x - 5

There is infinite discontinuity at x = 5. At this value, the graph becomes undefined because the denominator is 0.

5 0

3 years ago

Each lap around Spring Reservoir is 2 3/8 miles long. Terrence walked 2 1/2 laps around the Reservoir. How many miles did Terren

Arturiano [62]

Namely, how much is 2 and 1/2 of 2 and 3/8 then, well is just their product, let's first convert them both from mixed to "improper" and proceed.

$\bf \stackrel{mixed}{2\frac{3}{8}}\implies \cfrac{2\cdot 8+3}{8}\implies \stackrel{improper}{\cfrac{19}{8}}
\\\\\\
\stackrel{mixed}{2\frac{1}{2}}\implies \cfrac{2\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{5}{2}}\\\\
-------------------------------\\\\
\stackrel{laps~done}{\cfrac{5}{2}}\cdot \stackrel{\textit{miles in a lap}}{\cfrac{19}{8}}\implies \cfrac{95}{16}\implies \stackrel{miles}{5\frac{15}{16}}$

6 0

3 years ago

Which statement is true? Question 1 options: A) – |–13| = 13 B) – |13| = 13 C) |–13| = 13 D) |13| = – 13

ExtremeBDS [4]

Answer:

The answer is C. |-13| = 13

Step-by-step explanation:

The definition of absolute value is:

$\displaystyle \large{ |x| = \begin{cases} x \: \: (x \geqslant 0) \\ - x \: \: (x < 0) \end{cases}}$

To say it simply, any real numbers in absolute sign, when evaluated, they will always be positive.

No matter the positive real numbers or negative real numbers - if these numbers are in absolute sign, they will be evaluated to positive.

<u>E</u><u>x</u><u>a</u><u>m</u><u>p</u><u>l</u><u>e</u><u>s</u>

$\displaystyle \large{ |2| = 2} \\ \displaystyle \large{ | - 2| = 2} \\ \displaystyle \large{ | - 8| = 8}$

But if the negative is not inside the absolute sign.

<u>E</u><u>x</u><u>a</u><u>m</u><u>p</u><u>l</u><u>e</u><u>s</u><u> </u><u>I</u><u>I</u>

$\displaystyle \large{ - |2| = - 2} \\ \displaystyle \large{ - | - 2| = - 2} \\ \displaystyle \large{ - | - 8| = - 8}$

First, we evalute the absolute value first. We know thay any real numbers in absolute sign will become positive. Next, after evaluating the absolute value, we simply add the negative symbol beside the positive number.

<u>S</u><u>i</u><u>m</u><u>p</u><u>l</u><u>i</u><u>f</u><u>i</u><u>e</u><u>d</u><u> </u><u>D</u><u>e</u><u>f</u><u>i</u><u>n</u><u>i</u><u>t</u><u>i</u><u>o</u><u>n</u>

This one is to make it simple to remember.

$\displaystyle \large{ |a| = a} \\ \displaystyle \large{ | - a| = a} \\ \displaystyle \large{ - |a| = - a} \\ \displaystyle \large{ - | - a| = - a}$

After reading the explanation, see the choices and tell if they are true or not.

The A choice is wrong as we know that -|-13| is -13.

The B choice is wrong, the reason is same as the A choice.

The C choice is correct! Any real numbers in absolute sign are always positive.

The D choice is wrong because absolute-value numbers cannot be negative, refer to the C choice's reason.

Let me know if you have any questions!

3 0

3 years ago