Answer:
A. 162 m²
Step-by-step explanation:
==>Given:
Isosceles trapezoid with:
base a = 19m
base b = 35m
Perimeter = 74meters
==>Required:
Area of trapezoid
==>Solution:
Recall: the length of the legs of an isosceles trapezoid are equal.
Perimeter of isosceles trapezoid = sum of the parallel sides + 2(length of a leg of the trapezoid)
Let l = leg of trapezoid.
Perimeter = 74m
Sum of parallel sides = a+b = 19+35 = 54m
Thus,
74 = 54 + 2(l)
74 - 54 = 2(l)
20 = 2(l)
l = 20/2 = 10m
Let's find area:
Area = ½(a+b)*h
a = 19
b = 35
h = ?
Using Pythagorean theorem, let's find h as follows:
h² = l² - [(35-19)/2)²
h² = 10² - [16/2]²
h² = 100 - 64
h² = 36
h = √36 = 6m
Area = ½ x (a+b) × h
= ½ × (19+35) × 6
= ½ × 54 × 6
= 27 × 6
Area = 162m²
Answer:
21 degrees
Step-by-step explanation:
Triangles have a total angle of 180 degrees.
This makes our equation:
3x+3+4x+135=180
Subtract 135 from both sides and combine like terms
7x + 3 = 45
Subtract 3 from both sides
7x = 42
Divide both sides by 7
x = 6
Plugging the number in:
3x + 3 =
3(6) + 3 =
21
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You'll need to post the polynomial itself. The degree will be the highest exponent, the leading coefficient will be the number in front of the variable of the term with the highest exponent, then count the number of terms separated by + and - signs.
