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Helen [10]
3 years ago
7

-6a + 2a= -36 pls help

Mathematics
2 answers:
miv72 [106K]3 years ago
5 0

Answer:

a = 9

Step-by-step explanation:

-6a + 2a = -36

-4a = -36

a = -36/-4

a = 9

djyliett [7]3 years ago
4 0

Answer:

a=9

Step-by-step explanation:

-6a + 2a= -36

-4a = -36

÷-4    ÷-4

a= 9

<u><em>I HOPE THIS HELPS:)</em></u>

<u><em>HAVE A GOOD DAY</em></u>

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3845 divided by 0.07. Round to the nearest tenth.
IRINA_888 [86]

Answer: 55357.1


Step-by-step explanation: When you divide 3845 by 0.07 you get 553571.142857142857143. TTo round to the nearest tenth means the first decimal point which woukd make the answer 55357.1


5 0
3 years ago
To icrease an amount by 35% what single multiplier would u use
Pie
You would take your number, let's use 55, and multiply it by 0.35. 

55 x 0.35 = 20.25

Then add that answer to your original number.

55 + 20.25 = 75.25

Your answer is 17.25.
3 0
3 years ago
Simplify tan9x-tan5x / 1+tan9xtan5x<br> (SHOW WORK)
Charra [1.4K]

Answer:

The simplest form is tan(4x)

Step-by-step explanation:

* Lets revise the identity of the compound angles

- tan(a+b)=\frac{tan(a)+tan(b)}{1-tan(a)tan(b)}

- tan(a-b)=\frac{tan(a)-tan(b)}{1+tan(a)tan(b)}

* Lets solve the problem

- Let 9x = 5x + 4x

∴ tan(9x) = tan(5x + 4x)

- Use the rule of the compound angle

∵ \frac{tan(9x)-tan(5x)}{1+tan(9x)tan(5x)} ⇒ (1)

∵ tan(5x+4x)=\frac{tan(5x)+tan(4x)}{1-tan(5x)tan(4x)} ⇒ (2)

∵ tan(9x) = equation (2)

- Substitute (2) in (1)

∴ \frac{\frac{tan(5x)+tan(4x)}{1-tan(5x)tan(4x)}-tan(5x)}{1+(\frac{tan(5x)+tan(4x)}{1-tan(5x)tan(4x)})tan(5x)}

- Multiply up and down by (1 - tan(5x)tan(4x))

∴ \frac{tan(5x)+tan(4x)-tan(5x)[1-tan(5x)tan(4x)]}{1-tan(5x)tan(4x)+tan(5x)[tan(5x)+tan(4x)]}

- Simplify up and down

∴ \frac{tan(5x)+tan(4x)-tan(5x)+tan^{2}(5x)tan(4x)}{1-tan(5x)tan(4x)+tan^{2}(5x)+tan(5x)tan(4x) }

∴ \frac{tan(4x)+tan^{2}(5x)tan(4x)}{[1+tan^{2}(5x)]}

- Take tan(4x) as a common factor up

∴ \frac{tan(4x)[1+tan^{2}(5x)]}{[1+tan^{2}(5x)]}

- Cancel [1 + tan²(5x)] up and down

∴ The answer is tan(4x)

4 0
3 years ago
A dance class consists of 22 students, of which 10 are women and 12 are men. if 5 men and 5 women are to be chosen and then pair
OverLord2011 [107]

solution:

I choose 5 women from a pool of 10 in 10C2 ways.

I choose 5 men from a pool of 12 in 12C2 ways.

So total number of ways of choosing in 10C2 x 12C2. Now I need to arrange them in 5 pairs. This is where I have a different solution. The solution says that there are 5! ways to arrange them in pairs.

But I cant seem to understand why? My reasoning is that for first pair position I need to choose 1 man from 5 and 1 woman from 5. So for the first position I have 5 x 5 choices (5 for man and 5 for woman). Similarly for the second position I have 4 x 4 choices and so on. Hence the total ways are 5! x 5!

So I calculate the total ways as 10C2 * 12C2 * 5! * 5!. Can anyone point the flaw in my reasoning for arranging the chosen men and women in pairs.

3 0
4 years ago
The number of bones in a weightlifter's foot is 26 how many bones are there in the feet of 26 weightlifters
blsea [12.9K]

Answer:

1352 bones

Step-by-step explanation:

There are 26 bones in 1 foot

There are 2 feet per weightlifter

So each person has 2*26 = 52 bones in their feet

If we have 26 weightlifters, they have 52 bones in their feet.

26*52 = 1352 bones for 26 weightlifters for both feet

4 0
4 years ago
Read 2 more answers
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