The plane PRS passes through the points P, R and S. So it contains the line RS. Also the plane QRS passes through the points Q, R and S. So it contains the line RS as well. Since both the planes contain the line RS, the line RS must be the intersection of plane PRS and QRS
Answer:
y+1 = -1(x+10)
Step-by-step explanation:
The point slope equation of a line is
y-y1 = m(x-x1) where m is the slope and (x1, y1) is a point on the line
y - -1 = -1 (x --10)
y+1 = -1(x+10)
-9/5 or -1.8
2 - - 3 = 5
-5 - 4 = -9
X + y = 24
x - y = 2
Adding both equations
2x = 26
x = 13
y = 11
You plug in x + 8 for y in the second equation.
answer: x + x + 8 = 2
