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neonofarm [45]
3 years ago
10

Math word problem. What's the equation I use?

Mathematics
1 answer:
UkoKoshka [18]3 years ago
3 0
You would have to find the proportionality of the two.  If his shadow is 3 feet long, and the tree's shadow is 9 that means it is proportioned by 3. So the height of the tree would be 15.
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When p = 12, t = 2, and s = 1/6, r = 18. If r varies directly with p and inversely with the product of s and t, what is the cons
Ilia_Sergeevich [38]
R = kp/st
18 = 12k/(1/6 x 2)
18 = 12k/(1/3)
18 = 36k
k = 18/36 = 1/2

3 0
3 years ago
You have $1,500 to spend over a five month semester to cover your living expenses. In the first month, you spend $150 at restaur
alekssr [168]

Answer:

$250

Step-by-step explanation:

1st month you spent $300. And the flight back is $200. 300+200=500. 1500-500=1000. Yoy have 1000 dollars to spend in 4 months. 1000/4=250, so each month you can spend $250.

6 0
2 years ago
Read 2 more answers
Construct a 95​% confidence interval to estimate the population mean using the data below. x overbarequals37 sigmaequals10 nequa
kap26 [50]

Answer:

With 95% confidence when n equals 44, the population mean is between a lower limit of 33.96 and an upper limit of 40.04

Step-by-step explanation:

Confidence Interval = mean + or - Error margin (E)

mean = 37

sd = 10

n = 44

degree of freedom = n - 1 = 44 - 1 = 43

t-value corresponding to 43 degrees of freedom and 95% confidence level is 2.0165

E = t × sd/√n = 2.0165×10/√44 = 3.04

Lower limit = mean - E = 37 - 3.04 = 33.96

Upper limit = mean + E = 37 + 3.04 = 40.04

95% confidence interval is between 33.96 and 40.04

7 0
3 years ago
The slope and unit rate
Julli [10]
The slope is 4/5 I think
6 0
2 years ago
Sin α = 21/29, α lies in quadrant II, and cos β = 15/17, β lies in quadrant I Find sin (α - β).
Sever21 [200]
\sin(\alpha-\beta)=\sin\alpha\cos\beta-\cos\alpha\sin\beta

\sin\alpha=\dfrac{21}{29}\implies \cos^2\alpha=1-\sin^2\alpha=\dfrac{400}{841}

Since \alpha lies in quadrant II, we have \cos\alpha, so

\cos\alpha=-\sqrt{\dfrac{400}{841}}=-\dfrac{20}{29}

\cos\beta=\dfrac{15}{17}\implies\sin^2\beta=1-\cos^2\beta=\dfrac{64}{289}

\beta lies in quadrant I, so \sin\beta>0 and

\sin\beta=\sqrt{\dfrac{64}{289}}=\dfrac8{17}

So

\sin(\alpha-\beta)=\dfrac{21}{29}\dfrac{15}{17}-\left(-\dfrac{20}{29}\right)\dfrac8{17}=\dfrac{475}{493}
8 0
3 years ago
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