We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.
We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.
Formula for combination:

Where
represents the number of objects/people in the set and
represents the number of objects/people being chosen from the set
There are 23 people in the set and 10 people being chosen from the set


Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!
~ Padoru
Answer:
2.4 (2 2/5) pieces of pie per person.
Step-by-step explanation:
All that is needed to be done is simple division. Take your pieces of pie, (12) and divided it by the amount of people (5). This will give you 2.4. This can be turned into 24/10, and can be simplified twice. First to 12/5, then to 2 2/5.
Hope this helps!
Answer:
2
Step-by-step explanation:
Deal with the brackets first
(2x5) = 10
Then 10 cubed = 1000
Hope this helps