Answer:
2/3 or .66 repeated
Step-by-step explanation:
1 1/3= 1.33
1.33 + .66..7 is 2
Step-by-step explanation:
Answer:
There are 18 dimes and 12 quarters
Step-by-step explanation:
Remember that
1 Dime =$0.10
1 Quarter=$0.25
Let
x-----> the number of dimes
y-----> the number of quarters
we know that
x+y=30
x=30-y ------> equation A
0.10x+0.25y=4.80
Multiply by 100 both sides
10x+25y=480 ------> equation B
Substitute equation A in equation B and solve for y
10(30-y)+25y=480
300-10y+25y=480
15y=180
y=12 quarters
Find the value of x
x=30-y=30-12=18 dimes
therefore
There are 18 dimes and 12 quarters
Let x and y be the two integers.
The sum of the integers is x+y while the difference is x-y assuming x is larger than y.
If x+y > x-y, then
x+y > x-y
x+y-x > x-y-x
y > -y
y+y > -y+y
2y > 0
2y/2 > 0/2
y > 0
So as long as y is positive, this makes the sum greater than the difference
For example, if x = 10 and y = 2, then
x+y = 10+2 = 12
x-y = 10-2 = 8
clearly 12 > 8 is true
If y is some negative number (say y = -4), then
x+y = 10+(-4) = 10-4 = 6
x-y = 10-(-4) = 10+4 = 16
and things flip around
Saying a blanket statement "the sum of two integers is always greater than their difference" is false overall. If you require y to be positive, then it works but as that last example shows, it doesn't always work.
So to summarize things up, I'd say the answer is "no, the statement isn't true overall"
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