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2 years ago

A Two-Way Table

Mathematics

2 answers:

rusak2 [61]2 years ago

6 0

Answer:

B is the answer

Step-by-step explanation:

Just took the assignment

Morgarella [4.7K]2 years ago

5 0

48 boys

52 girls

I hope this helped you and I hope you have a good day

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Find the sum of the first 8 terms of the sequence. <br><br> 1, -3, -7, -11, ...

Darya [45]

$1+(-3)+(-7)+(-11)+(-15)+(-19)+(-23)+(-27) = \\1-3-7-11-15-19-23-27 = \\-35-19-23-27= \\-35-19-50=\boxed{-104}$

Hope this helps.

r3t40

4 0

3 years ago

Find the domain of f(x) = Square 3 x + 8

vagabundo [1.1K]

The question is a bit ambiguous: you may mean

$\sqrt{3x+8}$

$\sqrt{3x}+8$

Anyway, in both cases, the domain of a function involving a square root is found by imposing the content of the root to be greateer than or equal to zero. So, in the first case you have

$3x+8\geq 0 \iff 3x\geq -8 \iff x\geq -\dfrac{8}{3}$

In the second case, you have

$3x\geq 0 \iff x\geq 0$

6 0

3 years ago

Divide the polynomials. Your answer should be in this form p(x)+k/ x-3 where p is a polynomial and k is an integer. x^2+4/x-3=

Makovka662 [10]

Answer:

x + 3 + $\frac{13}{x-3}$

Step-by-step explanation:

Using long division

x + 3 ← quotient

--------------------------

x - 3 | x² + 0x + 4

x² - 3x ↓

------------------------

3x + 4

3x - 9

-----------------------

13 ← remainder

Thus

$\frac{x^2+4}{x-3}$ = x + 3 + $\frac{13}{x-3}$

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3 years ago

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2 years ago

Please answer both questions determine whether the function has an inverse function

Eduardwww [97]

Answer:

Pay attention to class

Step-by-step explanation:

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