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3 years ago

A < 1.5 how would i graph that on a numberline? Graph the inequality.

Mathematics

1 answer:

Oliga [24]3 years ago

7 0

Open circle with an arrow to the left of the number line with the circle on 1.5 in the middle of 1 and 2

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Find the quotient -72/-12=

natka813 [3]

answer is -72/-12 = 6

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3 years ago

Read 2 more answers

12x + 2y =6a. solve for yb. what is the slope and what is the y-intercept?

diamong [38]

The equation of a line in the slope intercept form is expressed as

y = mx + c

where

m represents slope

c represents y intercept

The given equation is

12x + 2y = 6

we would make this equation to look like the slope intercept equation.

12x + 2y = 6

If we subtract 12x from both sides of the equation, it becomes

12x - 12x + 2y = 6 - 12x

2y = 6 - 12x

2y = - 12x + 6

Dividing both sides of the equation by 2, it becomes

y = - 6x + 3

Thus, by comparing with the slope intercept equation,

slope = - 6

y intercept = 3

5 0

1 year ago

Square root of 2 times 3 to the square root of 2

bija089 [108]

Answer:

6.68754...

Step-by-step explanation:

Assuming you mean:

$\sqrt{2}\cdot 3^{\sqrt{2}}$

5 0

3 years ago

Hey can you please help me with this

Tasya [4]

x=-11

Hope this helps :T

8 0

3 years ago

For circle O, mCD=125° and m

Burka [1]

CA is a diameter of the circle, so $m\widehat{AC}=180^\circ$ , which means $m\angle AOB=m\angle AOD=m\widehat{AD}=180^\circ-m\widehat{CD}=55^\circ$ . Then $m\boxed{\angle ABO}=90^\circ-55^\circ=35^\circ$ .

This means $m\angle CBO=55^\circ-35^\circ=20^\circ$ . Also, if $m\angle AOB=55^\circ$ , then $m\angle BOC=180^\circ-55^\circ=125^\circ$ , which in turns tells us that $m\boxed{\angle BCO}=180^\circ-20^\circ-125^\circ=35^\circ$ .

3 0

3 years ago