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lord [1]
3 years ago
13

A < 1.5 how would i graph that on a numberline? Graph the inequality.

Mathematics
1 answer:
Oliga [24]3 years ago
7 0
Open circle with an arrow to the left of the number line with the circle on 1.5 in the middle of 1 and 2

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PLEASE HELP ME OUT ASAP!!! GEOMETRY! :V
Dima020 [189]
For the fish bowl the first answer is correct.
(1/2)(4/3)(22/7)(12^3)

For the second problem
(1/3)(3.14)(6^2)(10) - (4/3)(3.14)(1.5^3)
The second answer.
5 0
3 years ago
A physical therapist wants to determine the difference in the proportion of men and women who participate in regular sustained p
Oliga [24]

Answer:

no of sample within two percentage points  is 5409

no of sample not use prior​ estimates is 8321

Step-by-step explanation:

Given data

E = 2% = 0.02

male m = 21.2 % = 0.212

female f = 19.7 % = 0.197

to find out

no of sample within two percentage points and if does not use any prior​ estimates

solution

first we calculate no of sample within two percentage points

we know Z critical value for 99% is 2.58

so no of sample will be

n = (Z / E )² × m(1-m) + f ( 1-f )

put all the value we get no of sample

n = (2.58 / 0.02 )² × 0.212 ( 1 - 0.212 ) + 0.197 ( 1 - 0.197 )

n =  16641 ×0.3250

no of sample within two percentage points  is 5409

in 2nd part no of sample not use prior​ estimates

here than f and m will be 0.5

than

n = (Z / E )² × m(1-m) + f ( 1-f )

put all value

n = (2.58 / 0.02 )² × 0.5 ( 1 - 0.5 ) + 0.5 ( 1 - 0.5 )

n =  16641 ×  0.5

no of sample not use prior​ estimates is 8321

7 0
3 years ago
Solve 2cos ²y -siny -1=0 for 0° ≤y≤360°
natima [27]

 

\displaystyle\bf\\2cos^2y -sin\,y -1=0~~~for~~0^o\leq y \leq360^o\\\\cos^2y=1-sin^2y\\\\2(1-sin^2y) -sin\,y -1=0\\\\2-2sin^2y-sin\,y-1=0\\\\-2sin^2y-sin\,y+2-1=0\\\\-2sin^2y-sin\,y+1=0~~~\Big|\times(-1)\\\\2sin^2y+sin\,y-1=0

.

\displaystyle\bf\\\boxed{\bf sin\,y=x}\\\\2x^2+x-1=0\\\\x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-1\pm\sqrt{1-4\cdot2\cdot(-1)}}{2\cdot2}=\\\\=\frac{-1\pm\sqrt{1+8}}{4}=\frac{-1\pm\sqrt{9}}{4}=\frac{-1\pm3}{4}\\\\x_1=\frac{-1+3}{4}=\frac{2}{4}=\boxed{\bf\frac{1}{2}}\\\\x_2=\frac{-1-3}{4}=\frac{-4}{4}=\boxed{\bf-1}\\\\sin\,y=\frac{1}{2}\\\\\boxed{\bf y_1=\frac{\pi}{6}~~or~~(30^o)}\\\\\boxed{\bf y_2=\frac{5\pi}{6}~~or~~(150^o)}\\\\sin\,y=-1\\\\\boxed{\bf y_3=\frac{3\pi}{2}~~or~~(270^o)}

 

 

5 0
3 years ago
Complete the equation so that it represents the proportional relationship<br> shown in the table.
Bumek [7]
Answer: y= 4/3x
Explanation: the table is going up by 4/3
6 0
3 years ago
X^2-18x=-72<br><br> I need two solutions. Thanks.
eimsori [14]

Hey Astute!

Solve: x^2 - 18x = -72

Solution:

x^2 − 18x − (−72) = −72 − (−72) (Subtract -72 from both sides of the equation)

x^2 − 18x + 72 = 0

(x − 6) (x − 12) = 0 (Factor left side)

x − 6 = 0 or x − 12 = 0 (factors have to equal 0)

6 - 6 = 0 or 12 - 12 = 0

Answer:

x = 6 or x = 12

Hope This Helps, Have a Great Day!

7 0
3 years ago
Read 2 more answers
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