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Over [174]
3 years ago
12

Write the ratio as a fraction in simplest form with whole numbers in the 3.5 to 4.2

Mathematics
1 answer:
svp [43]3 years ago
5 0
\frac{3.5}{4.2} \times \frac{10}{10} = \frac{35}{42} = \frac{7\times 5}{7\times 6} \\\\ = \boxed{\bf{\frac{5}{6}}}
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15 decreased by twice a number x in algebriac expression
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2x - 15

15 is decreased that is the key word here which indicates subtraction.

twice a number with given variable x is 2x

subtraction always goes behind so 2x - 15
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A ______________________ does business in more than one country, has a global presence, thousands of employees, and well-known b
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It is a multinational coporation
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4 years ago
Read 2 more answers
Guys i need ur help fast please ​
Maslowich

Answer:

a) -3

b) 5

c) 7

d) 4

Step-by-step explanation:

We have the function p(x)=5x^3-3x^2+2x^5+7

a) We need to find the coefficient of x^2.

This means that we need to find out what number is alongside the x^2 in this equation. From the function, we can find that it is -3

b) Now we need to find the degree of p(x). Recall that the degree refers to the highest power of x that is present. As x^5 is the largest power, our degree would be 5.

c) The constant term refers to the number within the function that does not have any x's with it. In this function, that number would be 7.

d) Now we need to find the number of terms. For this one, we just need to count how many terms are separated by + or - signs. There are 4 in this function.

6 0
3 years ago
The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d
zaharov [31]

Answer:

P(61≤ X≤94) = 49.85%

Step-by-step explanation:

From the given information:

The mean of the bell shaped fluorescent light bulb μ = 61

The standard deviation σ = 11

The objective of this question is to determine the approximate percentage of light bulb replacement requests numbering between 61 and 94 i.e P(61≤ X≤94)

Using the empirical (68-95-99.7)rule ;

At 68% , the data lies between  μ - σ and μ + σ

i.e

61 - 11 and 61 + 11

50 and 72

At  95%, the data lies between  μ - 2σ and μ + 2σ

i.e

61 - 2(11) and 61 + 2(11)

61 - 22 and 61 +22

39   and   83

At 99.7%, the data lies between  μ - 3σ and μ + 3σ

i.e

61 - 3(11) and 61 + 3(11)

61 - 33 and 61 + 33

28   and   94

the probability equivalent to 94 is when  P(28≤ X≤94) =99.7%

This implies that ,

P(28≤ X≤94) + P(61≤ X≤94) = 99.7%

P(28≤ X≤94) = P(61≤ X≤94) = 99.7 %    

This is so because the distribution is symmetric about the mean

P(61≤ X≤94) = 99.7 %/2

P(61≤ X≤94) = 49.85%

5 0
3 years ago
What is the ratio for crayons to erasers?
gladu [14]

Answer:

8:4 simplified to 4:2 simplified to 2:1

Step-by-step explanation:

6 0
3 years ago
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