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7nadin3 [17]
3 years ago
9

the perimeter of a parallelogram is 72 meter. the width of the parallelogram is 4 meters less than its length. find the length a

nd the width of the parallelogram
Mathematics
1 answer:
xz_007 [3.2K]3 years ago
6 0
"<span>Start by setting up the standard equation for perimeter of a parallelogram, P=2w+2h (these variables of course being width and height). </span>
Now, substitute in what you know...

<span>The problem tells us that width is equal to height minus four. This means that, in order to keep only one variable in this problem, we will write width as h-4. </span>
<span>The problem also tells us that 72 is the perimeter, so we substitute that for P. </span>

72=2(h-4)+2h
<span>Now solve from here. </span>
<span>(Distribute first) </span>
72=2h-8+2h
(Combine like terms)
72=4h-8
80=4h
(Isolate h)
80/4=h
<span>20=h"</span>
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Find the real numbers x and y if -3+ix^2y and x^2+y+4i are conjugate of each other. Pls solve with the steps
Firdavs [7]
ANSWER
x = ±1 and y = -4.
Either x = +1 or x = -1 will work

EXPLANATION
If -3 + ix²y and x² + y + 4i are complex conjugates, then one of them can be written in the form a + bi and the other in the form a - bi. In other words, between conjugates, the imaginary parts are same in absolute value but different in sign (b and -b). The real parts are the same

For -3 + ix²y
⇒ real part: -3
⇒ imaginary part: x²y

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We have a system of equations since both conditions must be satisfied

   x²y = -4 ... (I)
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We can rearrange equation (II) so that we have

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Substituting into equation (I)

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Therefore, x = ±1.
Leave alone (x² + 4) as it gives no real solutions.

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   = 1 - 4 + 4i
   = -3 + 4i

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