Answer:
Today: Monday, 12 October 2020
Hour: 23.39 WIB (in Indonesia)
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-5x - - 4x - 10
-5x + 4x - 10
-x - 10
S = sisters ages
M =2S +7
M=13
13 = 2S+7
subtract 7 from each side
6 = 2S
divide by 2
3=S
sisters age is 3
Y = -3x - 1......so we sub in -3x - 1 in for y in the other equation
2x + 5y = 12
2x + 5(-3x - 1) = 12....now distribute the 5 through the parenthesis
2x - 15x - 5 = 12...add 5 to both sides
2x - 15x = 12 + 5..combine like terms
-13x = 17...divide both sides by -13
x = -17/13
now sub in -17/13 for x in the other equation
y = -3x - 1
y = -3(-17/13) - 1
y = 51/13 - 1
y = 51/13 - 13/13
y = 38/13
so the solution is (-17/13, 38/13)
Answer:
(4,11)
Step-by-step explanation:
y=2x+3
y=5x-9
the first equation is equal to the second equation so
2x+3=5x-9
put like terms together
2x-5x= -9-3
-3x= -12
divide both sides by -3
.•.x=4
now, use the value of x to find the value of y like this:
y=2x+3 (x=4)
y=2(4)+3
y=8+3
y=11
therefore, the two lines intersect at the point (4,11)
Answer:
f(x) = 4x^2 + 2x - 4.
Step-by-step explanation:
Let the quadratic function be y = f(x) = ax^2 + bx + c.
For the point (-2, 8) ( x = -2 when y = 8) we have:
a(-2)^2 + (-2)b + c = 8
4a - 2b + c = 8 For (0, -4) we have:
0 + 0 + c = -4 so c = -4. For (4, 68) we have:
16a + 4b + c = 68
So we have 2 systems of equations in a and b ( plugging in c = -4):
4a - 2b - 4 = 8
16a + 4b - 4 = 68
4a - 2b = 12
16a + 4b = 72 Multiplying 4a - 2b = 12 by 2 we get:
8a - 4b = 24
Adding the last 2 equations:
24a = 96
a = 4
Now plugging a = 4 and c = -4 in the first equation:
4(4) - 2b - 4 = 8
-2b = 8 - 16 + 4 = -4
b = 2.
