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3 years ago

13

What is 199•20+144 Thank you for those who answer

2 answers:

wel3 years ago

4 0

The answer is 4,124 hope this helped let me know

Troyanec [42]3 years ago

3 0

The answer to this question is 4124

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A garden has an area of 9 square meters. Each square is 1 square meter. What is the length of one side of this garden?

Llana [10]

The answer is 3, if it is in square meters it must be a square therefore each side is the same length

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3 years ago

Simplify to an expression of the form (a sin(θ)).<br> 2sin(/8)2cos(/8)

rjkz [21]

Answer:

Your expression equals $2 \sin(\frac{\pi}{4})$ assuming the problem was to simplify $2\sin(\frac{\pi}{8}) 2\cos(\frac{\pi}{8})$ to the form $a\sin(\theta)$ .

Step-by-step explanation:

$2\sin(\frac{\pi}{8}) 2\cos(\frac{\pi}{8})$

$2(2)\sin(\frac{\pi}{8})\cos(\frac{\pi}{8})$

Let's use the following identity: $2\sin(A)\cos(A)=\sin(2A)$

$2\sin(2 \cdot \frac{\pi}{8})$

$2 \sin(\frac{\pi}{4})$ which is comparable to the form $a\sin(\theta)$ .

$a=2$

$\theta=\frac{\pi}{4}$

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3 years ago

How many diagonals does a nanogon have

AleksandrR [38]

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3 years ago

Read 2 more answers

There are two vendors at the fair sleeping snow cones for the same price. If the containers are completely filled and then level

aliya0001 [1]

Answer:

$d = 787.81cm^3$

Step-by-step explanation:

Given

See attachment for the containers

Required

The difference in the amount of snow cone they hold

The amount they hold is determined by calculating the volume of the containers.

The traditional snow cone has the following dimension

Shape: Cone

$r=4cm$ --- radius

$h = 13cm$ --- height

The volume is calculated as:

$Volume = \frac{1}{3} \pi r^2h$

So, we have:

$V_1 = \frac{1}{3} \pi * 4^2 * 13$

$V_1 = \frac{208}{3} \pi$

The snow cone in a cup has the following dimension

Shape: Cylinder

$r=8cm$ --- radius

$h = 5cm$ --- height

The volume is calculated as:

$Volume = \pi r^2h$

So, we have:

$V_2 = \pi *8^2 * 5$

$V_2 = \pi *320$

$V_2 = 320\pi$

The difference (d) in the amount they hold is:

$d = V_2 - V_1$

$d = 320\pi - \frac{208\pi}{3}$

Take LCM

$d = \frac{3*320\pi -208\pi}{3}$

$d = \frac{960\pi -208\pi}{3}$

$d = \frac{752\pi}{3}$

Take $\pi = 22/7$

$d = \frac{752}{3} * \frac{22}{7}$

$d = \frac{752 * 22}{3*7}$

$d = \frac{16544}{21}$

$d = 787.81cm^3$

4 0

3 years ago

Pls help 100 points given to u

zimovet [89]

Answer:

9 is 2

10 is 6

Step-by-step explanation:

7 0

3 years ago