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3 years ago

14

Can yall go anwser my recent questions an comment when done ill give ou brainlest 100 pts.

2 answers:

Afina-wow [57]3 years ago

7 0

The correct answer is <u><em>No!!</em></u>

Hope This Helps!!!

SIZIF [17.4K]3 years ago

6 0

Answer:

No!!

Step-by-step explanation:

You might be interested in

Math 64 times40 eaquels 2.56

UkoKoshka [18]

Answer:

Wrong. It equals 2560.

Step-by-step explanation:

<h2><u><em>PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>

4 0

2 years ago

What is the absolute value of the difference in the x-values between (1,7) and (3,11)

Marysya12 [62]

Answer:

2.

Step-by-step explanation:

The first numbers in the ordered pairs are the x values;

Difference = 1 - 3 = -1

The absolute value is 2.

7 0

3 years ago

A shirt originally cost $39.38, but it is on sale for $31.50. What is the percentage decrease of the price of the shirt? If nece

seraphim [82]

Answer:

20%

Step-by-step explanation:

1. subtract the new price from the original price

$39.38-31.50=7.88$

2. divide the difference by the original number

$7.88$ ÷ $39.38$ $=.2001$

3. multiply this number by 100

$(.2001)100=20%$

5 0

3 years ago

Need help please. Thanks in advance

S_A_V [24]

3x+4=10
Subtract 4 from both sides
3x=6
Divide both sides by 3
X=2

Sides = 10,10,5

Problem 5. 4x+1=29
Subtract 1 from both sides
4x=28
X=7

7 0

3 years ago

A piece of cardboard has the dimensions (x + 15) inches by (x) inches with the area of 60 in 2 . Write the quadratic equation th

pochemuha

Answer:

$x^2 + 15x - 60 = 0$

The actual dimension is 18.28 by 3.28

Step-by-step explanation:

Given

Dimension:

$(x + 15)\ by\ x$

$Area = 60in^2$

Required

Determine the quadratic equation and get the possible values of x

Solving (a): Quadratic Equation.

The cardboard is rectangular in shape.

Hence, Area is calculated as thus:

$Area = Length * Width$

$60= (x + 15) * x$

Open Bracket

$60= x^2 + 15x$

Subtract 60 from both sides

$x^2 + 15x - 60 = 0$

<em>Hence, the above represents the quadratic equation</em>

Solving (b): The actual dimension

First, we need to solve for x

This can be solved using quadratic formula:

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

Where

$a = 1$

$b = 15$

$c = -60$

So:

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

$x = \frac{-15 \± \sqrt{15^2 - 4*1*-60}}{2*1}$

$x = \frac{-15 \± \sqrt{225 + 240}}{2}$

$x = \frac{-15 \± \sqrt{465}}{2}$

$x = \frac{-15 \± \21.56}{2}$

Split:

$x = \frac{-15 + 21.56}{2}$ or $x = \frac{-15 - 21.56}{2}$

$x = \frac{6.56}{2}$ or $x = \frac{-36.36}{2}$

$x = 3.28$ or $x = -18.18$

But length can't be negative;

So:

$x = 3.28$

The actual dimensions: $(x + 15)\ by\ x$ is

$Length =3.28 +15$

$Length =18.28$

$Width = x$

$Width =3.28$

<em>The actual dimension is 18.28 by 3.28</em>

3 0

3 years ago