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Flura [38]
3 years ago
11

I really need help on this asap make sure it right, please

Mathematics
2 answers:
Free_Kalibri [48]3 years ago
3 0

Answer:

102.5

Step-by-step explanation:

.4= 4

41=410

410/4= 102.5

OLEGan [10]3 years ago
3 0

Answer:102.5

Step-by-step explanation:

move the decimal on the outside alway to the outside of that area and then put a decimal in the in box but make sure you move the decimal 1 space to the right of the 1 then go from there and fill in the empty space with a 0.

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A phone company wants to know if its customers are satisfied with their service. 100 people are surveyed. The results show that
dolphi86 [110]

100:40

=2.5

1200 : 2.5

=480

5 0
3 years ago
I dont really understand this??​
jeyben [28]

Answer:

x\geq  -53

Step-by-step explanation:

The inequality includes -53.

The interval notation is \:[-53,\:\infty \:)

\{ x \in \mathbb{R}: x \geq  -53 \}

8 0
3 years ago
Read 2 more answers
When asked to write a point-slope equation for a line passing through the points (-2, -2) and (2, 1), a student wrote y - 1 = -3
bogdanovich [222]
B, hopefully that helps.
8 0
4 years ago
Need help pls. I try many ways of this answer
LekaFEV [45]

Answer:

3(t+2)

Step-by-step explanation:

As with any problem involving division of fractions, you can invert the denominator and multiply.

Your knowledge of the factoring of the difference of squares helps. If that doesn't work for you, you can always use synthetic division or polynomial long division to find the quotient of (t^2-4) and (t-2).

\displaystyle\frac{\frac{4t^2-16}{8}}{\frac{t-2}{6}}=\frac{4(t^2-4)}{8}\cdot\frac{6}{t-2}\\\\=\frac{3(t+2)(t-2)}{t-2}=3(t+2)

3 0
3 years ago
Cot²3x - 3cot3x +2 = 0<br> cotx = t<br> what equation for t
kumpel [21]

Answer:

Step-by-step explanation:

cot²(3x)=y

y²-3y+2=0

y²-y-2y+2=0

y(y-1)-2(y-1)=0

(y-1)(y-2)=0

y=1,y=2

cot3x=1

tan 3x=1=tan (π/4)=tan (nπ+π/4)

3x=nπ+π/4=(4nπ+π)/4=(4n+1)π/4

x=(4nπ+1)π/12,n is an integer.

cot 3x=2

tan 3x=1/2

3x=tan^{-1}(1/2)≈26.57°+360n

x≈8.86°+120n

6 0
3 years ago
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