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2 years ago

Someone please help!

Mathematics

1 answer:

USPshnik [31]2 years ago

6 0

Here are the log properties you need:
$log(ab) = log(a) +log(b) \\ \\ log(\frac{a}{b}) = log(a) - log(b) \\ \\ log(a^n) = n log(a)$

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In science class, Sarah calculates the mass of a planet to be 918,000,000,000,000,000,000 kg. What is the mass of the planet in

Alexeev081 [22]

Answer:

Step-by-step explanation:

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3 years ago

During the 7th examination of the Offspring cohort in the Framingham Heart Study, there were 1219 participants being treated for

AlexFokin [52]

Answer:

95% confidence interval for the proportion of the population which are on treatment is [0.3293 , 0.3607].

Step-by-step explanation:

We are given that during the 7th examination of the Offspring cohort in the Framing ham Heart Study, there were 1219 participants being treated for hypertension and 2,313 who were not on treatment.

The sample proportion is : $\hat p$ = x/n = 1219/3532 = 0.345

Firstly, the pivotal quantity for 95% confidence interval for the proportion of the population is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion = 0.345

n = sample of participants = 3532

p = population proportion

Here for constructing 95% confidence interval we have used One-sample z proportion statistics.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level of

significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

95% confidence interval for p= [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.345-1.96 \times {\sqrt{\frac{0.345(1-0.345)}{3532} } }$ , $0.345+1.96 \times {\sqrt{\frac{0.345(1-0.345)}{3532} } }$ ]

= [0.3293 , 0.3607]

Hence, 95% confidence interval for the proportion of the population which are on treatment is [0.3293 , 0.3607].

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2 years ago

Which system of equations can be used to find the roots of the equation 4x^2=x^3+2x?

irina [24]

Next time, please share the answer choices.
Starting from scratch, it's possible to find the roots:

4x^2=x^3+2x should be rearranged in descending order by powers of x:

x^3 - 4x^2 + 2x = 0. Factoring out x: x(x^2 - 4x + 2) = 0

Clearly, one root is 0. We must now find the roots of (x^2 - 4x + 2):

Here we could learn a lot by graphing. The graph of y = x^2 - 4x + 2 never touches the x-axis, which tells us that (x^2 - 4x + 2) = 0 has no real roots other than x=0. You could also apply the quadratic formula here; if you do, you'll find that the discriminant is negative, meaning that you have two complex, unequal roots.

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