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3 years ago

What is one-half of 3/4

Mathematics

2 answers:

Mnenie [13.5K]3 years ago

4 0

THE HALF OF 3/4 WOULD BE 0.375

liraira [26]3 years ago

3 0

one-half of 3/4 is 3/8.

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What is the rate change of the linear function that has a graph that passes through the points (2,9) (-1,3)

denis-greek [22]

Slope: (y2-y1)/(x2-x1)
(3-9)/(-1-2) = -6/-3 = 2
The rate of change is 2

8 0

3 years ago

The price of your service plan before taxes is 89.99. For your convenience, I will deduct 15% off your service plan before taxes

Citrus2011 [14]

First, you must find how much $ the discount takes off
89.99 * .15
=13.4985

Subtract that from 89.99

=76.4915

If you estimate it,
$ 76.49

5 0

3 years ago

A fireworks company has two types of rockets called Zinger 1 and Zinger 2. The polynomial -16t^2+150t gives the height in feet o

Alisiya [41]

The height of Zinger 1 after 6 seconds is given by the polynomial

$-16 t^{2}+150t$ , for t = 6,

so the height is $-16 *6^{2}+150*6=-576+900=324$ (feet)

The height of Zinger 2 after 6 seconds is given by the polynomial

$-16 t^{2}+165t$ , for t = 6,

so the height is $-16 *6^{2}+165*6=-576+990=414$ (feet)

At the moment the rockets explode, Zinger 2 is 414-324=90 (feet)

higher than Zinger 1.

Answer: 90 feet

7 0

3 years ago

3. Suppose the local Best Buy store averages 301 customers every day entering the facility with a standard deviation of 80 custo

stich3 [128]

Answer:

The probability that the average number of customers in the sample is between 290 and 310 is 0.61922.

Step-by-step explanation:

We are given that the local Best Buy store averages 301 customers every day entering the facility with a standard deviation of 80 customers.

A random sample of 50 business days was selected.

Let $\bar X$ = sample average number of customers

The z-score probability distribution for sample average is given by;

Z = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population average = 301 customers

$\sigma$ = population standard deviation = 80 customers

n = sample of business days = 50

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

(a) Probability the average number of customers in the sample is between 290 and 310 is given by = P(290 < $\bar X$ < 310) = P( $\bar X$ < 310) - P( $\bar X$ $\leq$ 290)

P( $\bar X$ < 310) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{310-301}{\frac{80}{\sqrt{50} } }$ ) = P(Z < 0.79) = 0.78524

P( $\bar X$ $\leq$ 290) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ $\leq$ $\frac{290-301}{\frac{80}{\sqrt{50} } }$ ) = P(Z $\leq$ -0.97) = 1 - P(Z < 0.97)

= 1 - 0.83398 = 0.16602

{Now, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.79 and x = 0.97 in the z table which has an area of 0.78524 and 0.83398 respectively.}

Therefore, P(290 < $\bar X$ < 310) = 0.78524 - 0.16602 = 0.61922

Hence, the probability that the average number of customers in the sample is between 290 and 310 is 0.61922.

4 0

3 years ago

Find the formula for an exponential function that passes through the two points given.

finlep [7]

This is graphing right ??

3 0

3 years ago