Answer:
There is no table, so I can only comment on the statements:
The binary value of decimal 10 is A. ==> False, however A is a hexadecimal representation of 10.
The binary value of decimal 13 is 1001 ==> False, 13 would be 1101.
The binary value of decimal 15 is 1111. ==> True.
The binary value of decimal 14 is E. ==> Again E is a hexadecimal representation of 14.
All of the given answer options are necessary to operate the enterprise resource planning (ERP) system when defining a system landscape.
Enterprise resource planning (ERP) can be defined as a business strategy process through which business firms manage and integrate the main parts of their day-to-day business activities by using software applications.
The main objective and purpose of an enterprise resource planning (ERP) system is to significantly reduce costs by integrating all the operations of a business firm.
In Computer science, when defining a system landscape, all of the following are necessary to operate the enterprise resource planning (ERP) system:
Read more on ERP system here: brainly.com/question/25752641
A. number of addresses is 65536
b. memory capacity is 128 kbytes or 131072 bytes
c. The last memory address is FFFF which is 65535
Answer:
% here x and y is given which we can take as
x = 2:2:10;
y = 2:2:10;
% creating a matrix of the points
point_matrix = [x;y];
% center point of rotation which is 2,2 here
x_center_pt = x(2);
y_center_pt = y(2);
% creating a matrix of the center point
center_matrix = repmat([x_center_pt; y_center_pt], 1, length(x));
% rotation matrix with rotation degree which is 45 degree
rot_degree = pi/4;
Rotate_matrix = [cos(rot_degree) -sin(rot_degree); sin(rot_degree) cos(rot_degree)];
% shifting points for the center of rotation to be at the origin
new_matrix = point_matrix - center_matrix;
% appling rotation
new_matrix1 = Rotate_matrix*new_matrix;
Explanation:
We start the program by taking vector of the point given to us and create a matrix by adding a scaler to each units with repmat at te center point which is (2,2). Then we find the rotation matrix by taking the roatational degree which is 45 given to us. After that we shift the points to the origin and then apply rotation ans store it in a new matrix called new_matrix1.
