Answer:
1.
DIM myArray(10) as INTEGER
LET A = 0
FOR I = 1 TO 10 STEP 2
INPUT “INPUT NUMBER”; myArray(i)
LET A = A + myArray(i)
NEXT
PRINT A
END
2.
REM PROGRAM FOR CALCULATING THE SIMPLE INTEREST
CLS
INPUT “INPUT THE PRINCIPAL”; P
INPUT “INPUT THE TIME”; T
INPUT “INPUT THE RATE”;R
SI = P* T * R / 100
PRINT “SIMPLE INTEREST =”; SI
END
Explanation:
Please find the respective programs in the answer section.
Answer:
a. Checksum
Explanation:
Based on the information provided within the question it can be said that the field that represents this information is called the Checksum. Like mentioned in the question this refers to a value that represents the amount of bits in a certain transmission message. This is done in order to make sure that the amount of bits that were sent match the amount that were received in order to make sure that no data was lost in transit that would cause high-level errors.
Answer:
The program to this question can be given as:
Program:
#include <stdio.h> //include header files
#include<math.h>
int main() //main method
{
double treeHeight = 0.0; //declare variables
and assign value
double shadowLength = 0.0;
double angleElevation = 0.11693706;
// (0.11693706 radians = 6.7 degrees) convert number into angle.
shadowLength = 17.5;
treeHeight = shadowLength * tan(angleElevation); //convert number into angle
printf("Tree height: %lf\n", treeHeight); //print value.
return 0;
}
Output:
Tree height: 2.055778
Explanation:
In the above C language program firstly we include the headers. In this header file, we include a (math.h) header file this file helps to use the math function. Then we declare the main method in the main method we declare the variable that is given in the question that are treeHeight, shadowLength , angleElevation. All the variable datatype is double because it stores the floating-point value. Then we apply the formula that is treeHeight = shadowLength * tan(angleElevation). In this formula, the treeHeight variable holds the value. Then we print the variable value for print the double value we use the lf(that is long float).
Windows OS and Mac OS are examples of single user, multi tasking Operating Systems.
Answer:
No, It will not. but sometimes when you do the overclock the monitor may not have fast enough pixel response time. you might notice some tearing in the image. but will not do any permit damage
Explanation:
my display is overclocked from 60hz to 75hz (the max)
