Answer:
Perimeter of given regular hexagon is <em>48.5 ft</em>.
Step-by-step explanation:
Let <em>ABCDEF</em> be the regular hexagon as shown in the attached figure.
<em>O</em> be the intersection point of the diagonals <em>EB</em>, <em>FC </em>and <em>AD</em>.
As per the property of regular hexagon, all the 6 triangles formed are equilateral triangles.
In other words,
are equilateral
.
Area of an equilateral is defined as
:
Where <em>a </em>is the side of .
Area of hexagon =
We are given that area of hexagon = 169.74
Let <em>s </em>be the side of hexagon.
A regular Hexagon is made up of 6 equal sides, so
Perimeter of a regular hexagon =
Perimeter =
So, perimeter of given regular hexagon is .
