Answer:
(a) The value of C is 1.
(b) In 2010, the population would be 1.07555 billions.
(c) In 2047, the population would be 1.4 billions.
Step-by-step explanation:
(a) Here, the given function that shows the population(in billions) of the country in year x,

So, the population in 2000,



According to the question,


(b) Similarly,
The population in 2025,


(∵ C = 1)
Again according to the question,


Taking ln both sides,




Thus, the function that shows the population in year x,
...... (1)
The population in 2010,
Hence, the population in 2010 would be 1.07555 billions.
(c) If population P(x) = 1.4 billion,
Then, from equation (1),







Therefore, the country's population might reach 1.4 billion in 2047.