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wel
3 years ago
7

What is 3m + 10 = 30

Mathematics
2 answers:
iragen [17]3 years ago
7 0

Answer:

"M" would equal 6.6 repeated

Step-by-step explanation:

DaniilM [7]3 years ago
7 0

Answer:

Step-by-step explanation:

3m + 10= 30

3m =30-10

3m=20

m= 20/3

m= 6.67

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WILL GIVE THE BRAINLIEST. PLEASE HELP.
stiks02 [169]

Answer:

300 miles.

Step-by-step explanation:

Distance = Rate * Time

We know the rate, 80 miles per hour.

We know the time, 3.75 hours.

As these use the same time unit, hours, we don't need to change any values.

We can just put these values into the formula:

d=r*t

d=80*3.75=300

Answer: 300 miles.

3 0
3 years ago
Read 2 more answers
What is the answer for this -12n - (-13n)=
Ksenya-84 [330]

Answer:

n

Step-by-step explanation:

-12n - (-13n) = -12n +13n = 1n

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2 years ago
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julia-pushkina [17]

Answer:

d

Step-by-step explanation:

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6 0
2 years ago
First question, thanks. I believe there should be 3 answers
zysi [14]

Given: The following functions

A)cos^2\theta=sin^2\theta-1B)sin\theta=\frac{1}{csc\theta}\begin{gathered} C)sec\theta=\frac{1}{cot\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}

To Determine: The trigonometry identities given in the functions

Solution

Verify each of the given function

\begin{gathered} cos^2\theta=sin^2\theta-1 \\ Note\text{ that} \\ sin^2\theta+cos^2\theta=1 \\ cos^2\theta=1-sin^2\theta \\ Therefore \\ cos^2\theta sin^2\theta-1,NOT\text{ }IDENTITIES \end{gathered}

B

\begin{gathered} sin\theta=\frac{1}{csc\theta} \\ Note\text{ that} \\ csc\theta=\frac{1}{sin\theta} \\ sin\theta\times csc\theta=1 \\ sin\theta=\frac{1}{csc\theta} \\ Therefore \\ sin\theta=\frac{1}{csc\theta},is\text{ an identities} \end{gathered}

C

\begin{gathered} sec\theta=\frac{1}{cot\theta} \\ note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ tan\theta cot\theta=1 \\ tan\theta=\frac{1}{cot\theta} \\ Therefore, \\ sec\theta\ne\frac{1}{cot\theta},NOT\text{ IDENTITY} \end{gathered}

D

\begin{gathered} cot\theta=\frac{cos\theta}{sin\theta} \\ Note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ cot\theta=1\div tan\theta \\ tan\theta=\frac{sin\theta}{cos\theta} \\ So, \\ cot\theta=1\div\frac{sin\theta}{cos\theta} \\ cot\theta=1\times\frac{cos\theta}{sin\theta} \\ cot\theta=\frac{cos\theta}{sin\theta} \\ Therefore \\ cot\theta=\frac{cos\theta}{sin\theta},is\text{ an Identity} \end{gathered}

E

\begin{gathered} 1+cot^2\theta=csc^2\theta \\ csc^2\theta-cot^2\theta=1 \\ csc^2\theta=\frac{1}{sin^2\theta} \\ cot^2\theta=\frac{cos^2\theta}{sin^2\theta} \\ So, \\ \frac{1}{sin^2\theta}-\frac{cos^2\theta}{sin^2\theta} \\ \frac{1-cos^2\theta}{sin^2\theta} \\ Note, \\ cos^2\theta+sin^2\theta=1 \\ sin^2\theta=1-cos^2\theta \\ So, \\ \frac{1-cos^2\theta}{sin^2\theta}=\frac{sin^2\theta}{sin^2\theta}=1 \\ Therefore \\ 1+cot^2\theta=csc^2\theta,\text{ is an Identity} \end{gathered}

Hence, the following are identities

\begin{gathered} B)sin\theta=\frac{1}{csc\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}

The marked are the trigonometric identities

3 0
1 year ago
The probability of getting a 4- bedroom home with a open porch based off the table.
AleksandrR [38]
All you have to do is multiply 1/3 (the chance of getting a 4 bedroom home) times 1/2 (the chance of getting an open porch). The answer is a 1/6 chance, as you don’t have to do anything with the kitchens because the question doesn’t specify to.

Hope this helps!
4 0
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