All categories

3 years ago

What’s the distributive property of x(x+3)?

Mathematics

1 answer:

Alik [6]3 years ago

8 0

Answer:

X^2+3x

Step-by-step explanation:

X times x equals x^2

X times 3 equals 3x

separated by an addition sign so x^2+3x is the answer

You might be interested in

What does 144 =to for a squared

Dafna11 [192]

12 *12 = 144

Therefore 12^2 = 144

5 0

2 years ago

Read 2 more answers

I just learned this today and it’s a little confusing , is there anyone that could explain how to do these problems for me ?

evablogger [386]

Step-by-step explanation:

I'll do the first problem as an example.

∠P and ∠H both have one mark. That means they're congruent.

∠T and ∠G both have two marks. So they're congruent.

∠W and ∠D both have three marks. So they're congruent.

So we can write a congruence statement:

ΔPTW ≅ ΔHGD

We can write more congruence statements by rearranging the letter, provided that corresponding pairs have the same position (P is in the same place as H, etc.). For example:

ΔWPT ≅ ΔDHG

ΔTWP ≅ ΔGDH

3 0

3 years ago

If (x/3)-1 is twice as large as (x/4)-3, what is the value of x?

Ganezh [65]

Answer:

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

GRE Test: The Graduate Record Examination (GRE) is a test required for admission to many US graduate schools. Student’s scores o

Zepler [3.9K]

Answer:

a) $\bar X=144.3$

b) The 95% confidence interval would be given by (138.846;149.754)

c) n=34

d) n=298

e) n=1190

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

We can calculate the sample mean with this formula:

$\bar X = \frac{\sum_{i=1}^n x_i}{n}$

$\bar X=144.3$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=8.8$ represent the population standard deviation

n=10 represent the sample size

a) Find a point estimate of the population mean

We can calculate the sample mean with this formula:

$\bar X = \frac{\sum_{i=1}^n x_i}{n}$

$\bar X=144.3$

b) Construct a 95% confidence interval for the true mean score for this population.

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $t_{\alpha/2}=1.96$

Now we have everything in order to replace into formula (1):

$144.3-1.96\frac{8.8}{\sqrt{10}}=138.846$

$144.3+1.96\frac{8.8}{\sqrt{10}}=149.754$

So on this case the 95% confidence interval would be given by (138.846;149.754)

Part c

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =+20 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got $z_{\alpha/2}=1.960$ , replacing into formula (5) we got: