ΔACD is similar to ΔBCD by AA similarity theorem
AD/AC = BD/BC
x/5 = 4.2/6
6x = 21
x = 3.5
Hope this helps! ;)
Answer:
Step-by-step explanation:
Given are two rectangles MNOL and IJKH
MNOL is the image and IJKH is the preimage.
OBviously similarity is preserved between these.
Hence sides will be proportional
i.e. l1/l2 = w1/w2 = Scale factor k
This can also be written as
Scale factor square = 
Scale factor = square root of ratio of rectangle areas
Find ratio as
k = Scale factor = square root of the above fraction
=
The answer to your question is: Yes, someone undoubtedly can.
Although you haven't asked to be told or shown how to solve it, I'm here
already, so I may as well stick around and go through it with you.
The sheet is telling you to find the solutions to two equations, AND THEN
DO SOMETHING WITH THE TWO SOLUTIONS. But you've cut off the
instructions in the pictures, so all we have are the two equations, and
you'll have to figure out what to do with their solutions.
<u>First equation:</u>
(2/5) x - 6 = -2
Add 6 to each side:
(2/5) x = 4
Multiply each side by 5:
2x = 20
Divide each side by 2 :
<u>x = 10</u>
<u>Second equation:</u>
-3y + 1/4 = 13/4
Subtract 1/4 from each side:
-3y = 12/4
Multiply each side by 4 :
-12 y = 12
Divide each side by -12 :
<u> y = -1</u>
Answer:
the area would be 36(pi) since you can't find out the exact value of pi (22/7) and where it would terminate so thats the most exact answer you can get. The circumference would be
Step-by-step explanation:
12/2 = 6
Area = (pi)radius^2
6^2 = 36
36(pi)
Circumference: (pi)d
12(pi)
For approximate area you multiply r^2 by 3.14
For approximate circumference you multiply diameter by 3.14
