Xy=-36

x+y=-3

x= -36/y

-36/y + y = -3

-36 + y^2 = -3y

y^2 +3y -36 = 0

I think you have to use quadratic formula to find the 2 values of y and then plug in for x

3 0

3 years ago

What integer solves the expression 4 - -5 explain.

AnnZ [28]

Answer:

Step-by-step explanation:

the answer is 1

6 0

3 years ago

i already have the answers but i need to show my work. ill tell you my insta and please show me a picture of the work :))

Elodia [21]

Answer:

${( - 6)}^{2} \times {( - 6)}^{5}$

from law of indices:

${a}^{n} \times {a}^{m} = {a}^{(n + m)}$

therefore:

$= ( - 6) {}^{ \{2 + 5 \}} \\ = ( - 6) {}^{7} \\ = { \boxed{ \boxed{ - 279936}}}$

$- 4 {a}^{5} (6 {a}^{5} ) \\ = ( - 4 \times 6)( {a}^{5} \times {a}^{5} ) \\ = - 24 \{{a}^{(5 + 5)} \} \\ = { \boxed{ \boxed{ - 24 {a}^{10} }}}$

$( - 7 {a}^{4} b {c}^{3} )(5a {b}^{4} {c}^{2} ) \\ = ( - 7 \times 5)( {a}^{4} \times a)(b \times {b}^{4}) \times ( {c}^{3} \times {c}^{2} ) \\ = - 35 {a}^{5} {b}^{5 } {c}^{5} \\ = { \boxed{ \boxed{ - 35 {(abc)}^{5} }}}$

$\frac{ {8}^{15} }{ {8}^{13} }$

from law of indices:

$\frac{a {}^{n} }{ {a}^{m} } = {a}^{(n - m) } \\$

therefore:

$= {8}^{(15 - 13)} \\ { \boxed{ \boxed{ {8}^{2} = 64 }}}$

follow the procedure for application to other questions.

Any question, be free to ask. Thank you …

6 0

3 years ago

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