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Anettt [7]
3 years ago
13

According to records from the last 50 years, there is a 2/3 chance of June temperatures being above 80 F. Azul needs to find the

probability that it will be above 80' F for 20 or more days this June. There are 30 days in June. Use the simulation data to find the probability
Mathematics
2 answers:
dangina [55]3 years ago
6 0
Here we shall use the binomial distribution formula to evaluate the probability:
let the probability that the temp will be above 80 be P(F)=2/3; 
Probability that the temp will be below 80 be P(F')=1/3
thus, 
The probability that the temp will be above 80 for 20 days for the month of June will be:
P(F)=n!/((n-x)!x!)p^xq^(n-x)
p=2/3 and q=1/3, n=30, x=20
plugging the values in the equation we obtain:
P(F)=30!/(10!*20!)*(2/3)^20*(1/3)^(30-20)
P(F)=0.153



nexus9112 [7]3 years ago
3 0

The answer is 52%

Add all the answers from 20 up then find the percentage and you will have your answer,52.

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12345 [234]

The given equation is

m = ak/n

We want to solve for k

The first step is to multiply both sides of the equation by n. We have

m * n = ak/n * n

mn = ak

The next step is to divide both sides of the equation by a. We have

mn/a = ak/a

mn/a = k

k = mn/a

The correct option is the second one

7 0
1 year ago
Samantha ran on a fitness track for 20 ​min, and then walked for 15 min. Her running rate was 230 ft per minute faster than her
Mnenie [13.5K]

Answer:

  560 ft/min

Step-by-step explanation:

Let r represent Samantha's running rate in feet per minute. Then r-230 is her walking rate. We can use the relation ...

   distance = speed × time

to write an equation for the total distance Samantha went.

  20r + 15(r -230) = 16150

  35r - 3450 = 16150 . . . . eliminate parentheses, collect terms

  35r = 19600 . . . . . . . . . . add 3450

  r = 560 . . . . . . . . . . . . . . divide by the coefficient of r

Samantha ran 560 feet per minute.

5 0
3 years ago
Which term in the quotient of this expression contains an error?
Savatey [412]

Answer:

The + 78 :-  it should be + 60.

Step-by-step explanation:

Long division:-

x - 3 )4x^4 - 6x^3 + 0x^2 + 6x + 3 ( 4x^3 + 6x^2 + 18x + 60 <--- Quotient.

         4x^4 - 12x^3

                      6x^3 + 0x^2

                       6x^2 - 18x^2

                                   18x^2 + 6x

                                    18x^2 - 54x

                                                 60x + 3

                                                  60x - 180

                                                              183

7 0
3 years ago
Suppose Kalvin spins the pointer 64 times. Based on your experiment, how many times can you expect the pointer to land on 9:00,
Brrunno [24]

Answer:

16 times out of 64

Step-by-step explanation:

So, I could be wrong, but basically:

9, 10, and 11 are only 3 of the 12 possible outcomes that could happen.

3 out of 12 is 1/4.

What this means is that for every 4 times he spins the pointer, he can expect to get 9, 10, or 10 once.

Or 25% of the time

1/4 of 64 is 16.

4 0
3 years ago
Researchers have found that after 25 years of age the average size of the pupil in a
laila [671]

Answer:

At 25 = 6.8612mm

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Step-by-step explanation:

Equation,

d = 2.115Logₑa + 13.669

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a = number of years

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d = 2.115Ina + 13.669

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d = -2.115 × 3.2188 + 13.669

d = -6.807762 + 13.669

d = 6.8612mm

At 25 years, the pupil shrinks by 6.86mm

2. At 50 years,

d = -2.1158In50 + 13.669

d = -2.1158 * 3.912 + 13.669

d = -8.2770 + 13.699

d = 5.422mm

At 50 years, the pupil shirks by 5.422mm

To save this question, I had to plug in the values into the equation.

Solving for Logₑa might be difficult, so instead I used Inx which is the same thing. Afterwards, i substituted in the values and solve the equation for each years.

8 0
3 years ago
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