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cestrela7 [59]
3 years ago
7

Josh will run at least 35 miles this week. So far, he has run 19 miles. What are the possible numbers of additional miles he wil

l run? Use t for the number of additional miles he will run. Write your answer as an inequality solved for t .
Mathematics
1 answer:
Anit [1.1K]3 years ago
3 0

The possible numbers of additional miles he will run will be: t\geq 16

<u><em>Explanation</em></u>

So far, Josh has run 19 miles and the number of additional miles he will run in this week is  t miles.

Given that, he will run at least total 35 miles this week. That means the minimum total distance, he will run in this week is 35 miles.

So, the inequality will be.....

t+19\geq 35\\ \\ t\geq 35-19\\ \\ t\geq 16

Thus, he need to run at least 16 additional miles in this week.

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Answer:

A) Between 388 and 450

B) Between 357 and 481

C) Between 326 and 512

D) 99.995%

E) 72.907%

Step-by-step explanation:

We are given;

Mean; x¯ = 419 minutes

Standard deviation; σ = 31 minutes

A) From the empirical rule, 68% falls within 1 standard deviation.

Thus, it will be between;

419 - 1(31) and 419 + 1(31)

Thus gives;

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B) From the empirical rule, 95% falls within 2 standard deviation.

Thus, it will be between;

419 - 2(31) and 419 + 2(31)

Thus gives;

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C) From the empirical rule, 99.7% falls within 2 standard deviations.

Thus, it will be between;

419 - 3(31) and 419 + 3(31)

Thus;

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D)between 359 and 479 minutes, we will use z-s roe formula;

z = (479 - 359)/31

z = 3.871

From the z-table attached, we see that the probability is 0.99995 and as such, the percentage is 99.995%

E) worker spent 400 minutes on the job.

Thus;

z = (419 - 400)/31

z = 0.613

From z-tables, p = 0.72907

In percentage, we have; 72.907%

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