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2 years ago

The perimeter of a rectangular garden is 43.8 feet. It’s length is 12.4 feet. What is it’s width?

Mathematics

1 answer:

Stells [14]2 years ago

8 0

Answer:

9.5 m

Step-by-step explanation:

If width is -- x

12.4 + x + 12.4 + x = 43.8

2x = 19

x = (19/2)

x = 9.5 m

Thenks and mark me brainliest :))

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The circle below is centered at the point (4,3) and has a radius of length 5.

Lilit [14]

Answer:

B. (x-4)^2 + (y - 3)^2 = 5^2

Step-by-step explanation:

The equation for a circle is given by

(x-h)^2 + (y-k) ^2 = r^2

where (h,k) is the center and r is the radius

We have a center of (4,3) and a radius of 5

(x-4)^2 + (y-3) ^2 = 5^2

4 0

3 years ago

I really need the help please and thank you

Umnica [9.8K]

Answer:

B. $f^{-1}(x)=\frac{x-4}{5}$

Step-by-step explanation:

To find the inverse of a function/equation:

Replace f(x) with y: y=5x+4
Switch x and y: x=5y+4
Solve for y: x-4=5y -> $y=\frac{x-4}{5}$
Write in standard inverse notation: $f^{-1}(x)=\frac{x-4}{5}$

I hope this helps!!

gl!

3 0

2 years ago

he radioactive element carbon-14 has a half-life of 5750 years. A scientist determined that the bones from a mastodon had lost

elena-s [515]

Answer:

The bones were 12,485 years old at the time they were discovered.

Step-by-step explanation:

Amount of the element:

The amount of the element after t years is given by the following equation, considering the decay rate proportional to the amount present:

$A(t) = A(0)e^{-kt}$

In which A(0) is the initial amount and k is the decay rate, as a decimal.

The radioactive element carbon-14 has a half-life of 5750 years.

This means that $A(5750) = 0.5A(0)$ , and we use this to find k. So

$A(t) = A(0)e^{-kt}$

$0.5A(0) = A(0)e^{-5750k}$

$e^{-5750k} = 0.5$

$\ln{e^{-5750k}} = \ln{0.5}$

$-5750k = \ln{0.5}$

$k = -\frac{\ln{0.5}}{5750}$

$k = 0.00012054733$

$A(t) = A(0)e^{-0.00012054733t}$

A scientist determined that the bones from a mastodon had lost 77.8 % of their carbon-14. How old were the bones at the time they were discovered?

Had 100 - 77.8 = 22.2% remaining, so this is t for which:

$A(t) = 0.222A(0)$

Then

$0.222A(0) = A(0)e^{-0.00012054733t}$

$e^{-0.00012054733t} = 0.222$

$\ln{e^{-0.00012054733t}} = \ln{0.222}$

$-0.00012054733t = \ln{0.222}$

$t = -\frac{\ln{0.222}}{0.00012054733}$

$t = 12485$

The bones were 12,485 years old at the time they were discovered.

8 0

2 years ago

Please show step by step answer NO MIXED NUMBER/DECIMAL ANSWERS!!!

PolarNik [594]

Answer:

Step-by-step explanation:

5 0

1 year ago

Read 2 more answers

Solve for z z/12 equals 4/5

eimsori [14]

This is a proportion problem.

z 4
--- = ----
12 5

We can cross multiply and divide.

5z = 48
z = 9.6

Hope this helps!

7 0

2 years ago