A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
Answer:
A is the answer
Step-by-step explanation:
Becuase if it has the same radius and the same height. then they will both be equal.
D(1,-5,-4,-7) R(0,7,-7,-4) Domain are your x values and range is your y values
Answer:
1250000
Step-by-step explanation:
Let number of the total number of shoes sold be 'y'
y*(70/100)= 875000
70y = 875000*100
y = (875000*100)/70
y = 1250000
1 1/2 can be rewritten as 3/2
Difference means subtraction
So we do:
3/2-1/4
To get the same denominator, we can multiply the first fraction by 2
6/4-1/4
Then we subtract the numerators and leave the denominator
So the final answer is 5/4 of 1 1/4
Hope this helps
