Answer:
<h3><ABC > <DBC.</h3>
Step-by-step explanation:
Given < DBC = < RST and we need to prove < ABC is greater than <RST.
First given statement:
< DBC = < RST
Reason: Given.
Second given statement :
<ABC = <DBC+ <ABD.
Reason: Angle addition theorem.
<em>Note: < ABC is the sum of angles <DBC and <ABD and we have < DBC = < RST. So it's an obvious thing that the sum of angles <DBC and <ABD is always greater than <RST.</em>
Also, <ABC is greater than <DBC.
Therefore, correct option for third statement is :
<h3><ABC > <DBC.</h3>
The second one because there is all the inputs are different. There is one input for every output.
The answer is 225
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The linear model of this case takes the form:
y = a(x-b) + k
<span>The cost of having a package delivered has a base fee of $9.70
this is "k" >>>>> k=9.7 (fixed amount of fee)
THEN
</span>
<span>Every pound over 5 lbs cost an additional $0.46 per pound
that means: 0.46(x-5)
in other words, if the package weighs foe example 9 pounds, then 9-5=4, it will cost 0.46*4 for these 4 extra pounds
Finally we have the linear form of this: C = 0.46 (W - 5) + 9.7
</span>
