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evablogger [386]
3 years ago
8

You enter a relay race. To start, you must run 20 yards to Checkpoint A. You then must turn and run 12 yards to Checkpoint B. La

st, you must turn and run back to the starting line. What is the distance from Checkpoint B to the starting line? THANKS :)
Mathematics
2 answers:
Anarel [89]3 years ago
7 0

Distance to checkpoint A from starting line = 20 yards.

Then from A to B distance = 12 yards.

Let us take starting point C.

So, it would make a right triangle.

We have AB = 12, AC = 20, we need to find BC, that is Hypotenuse of the right triangle.

According to Pythagoras theorem:

BC^2 = AB^2+AC^2

BC^2 = 12^2+20^2

BC^2 = 144 +400 = 544

BC= \sqrt{544}

BC = 23.32.

<h3>Therefore,  23.32 yards is the distance from Checkpoint B to the starting line.</h3>
ella [17]3 years ago
6 0

Answer:

The shortest distance between checkpoint A and checkpoint B is 23.33 yards.        

Step-by-step explanation:

We are given the following information in the question:

Let O be the starting point.

Distance between the starting point and checkpoint A = 20 yards

To reach checkpoint B, one need to take a turn and let it be a 90 degrees turn toward right or left.

Distance between checkpoint A and checkpoint B = 12 yards

In order to find the shortest distance between the checkpoint A and checkpoint B, the displacement, we use the Pythagoras theorem.

Statement:

In  a right angled triangle:

(Side 1)^2 + (Side 2)^2 = (Hypotenuse)^2

(OA)^2 + (AB)^2 = (AB)^2\\(20)^2 + (12)^2 = (AB)^2\\400 + 144 = (AB)^2\\(AB)^2 = 544\\AB = \sqrt{544} \approx 23.33

Hence, the shortest distance between checkpoint A and checkpoint B is 23.33 yards.

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Any suggestions or answers
Sati [7]

Answer:

x=81\degree

y=99\degree

z=129\degree

Step-by-step explanation:

The sum of the interior angles of a triangle is 180 degrees.

\implies 51\degree+48\degree+x=180\degree

\implies 99\degree+x=180\degree

\implies x=180\degree-99\degree

\implies x=81\degree

Use the exterior  angles theorem to find y.

The exterior angle y is the sum of the two remote interior angles:

y=51\degree+48\degree=99\degree

The sum of angles on a straight line is 180 degrees.

\implies z+51\degree=180\degree

\implies z=180\degree-51\degree

\implies z=129\degree

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4 years ago
Which equation could be used to solve for the measure of side Q in the triangle QRS shown below given...
Rama09 [41]

The image is missing, so i have attached it

Answer:

Equation is;

q/sin 105 = 15/sin 30

Step-by-step explanation:

We are given;

Angle Q = 105°

Angle S = 30°

s = 15

From sine rule we know that;

a/sin A = b/sin B = c/sin C.

Thus, applying that to this question, we can find side q.

Thus;. q/Sin Q = s/Sin S

Plugging in the relevant values to obtain ;

q/sin 105 = 15/sin 30

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Step-by-step explanation:

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