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icang [17]
2 years ago
7

Two times the sum of a number and 8 equals 4

Mathematics
1 answer:
zhuklara [117]2 years ago
7 0

Answer:

8+4 is equal to 12

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Find the missing number 1:2 = 3: ____
Llana [10]
1:2=3:6
the missing number is 6
:)
8 0
3 years ago
Sequence 120 300 750
likoan [24]

Answer:

2.5

Step-by-step explanation:

This is a geometric sequence that increases by 2.5x.

120 x 2.5 = 300

300 x 2.5 = 750

Hope this helps!

7 0
3 years ago
Find the two intersection points
bogdanovich [222]

Answer:

Our two intersection points are:

\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)

Step-by-step explanation:

We want to find where the two graphs given by the equations:

\displaystyle (x+1)^2+(y+2)^2 = 16\text{ and } 3x+4y=1

Intersect.

When they intersect, their <em>x-</em> and <em>y-</em>values are equivalent. So, we can solve one equation for <em>y</em> and substitute it into the other and solve for <em>x</em>.

Since the linear equation is easier to solve, solve it for <em>y: </em>

<em />\displaystyle y = -\frac{3}{4} x + \frac{1}{4}<em />

<em />

Substitute this into the first equation:

\displaystyle (x+1)^2 + \left(\left(-\frac{3}{4}x + \frac{1}{4}\right) +2\right)^2 = 16

Simplify:

\displaystyle (x+1)^2 + \left(-\frac{3}{4} x  + \frac{9}{4}\right)^2 = 16

Square. We can use the perfect square trinomial pattern:

\displaystyle \underbrace{(x^2 + 2x+1)}_{(a+b)^2=a^2+2ab+b^2} + \underbrace{\left(\frac{9}{16}x^2-\frac{27}{8}x+\frac{81}{16}\right)}_{(a+b)^2=a^2+2ab+b^2} = 16

Multiply both sides by 16:

(16x^2+32x+16)+(9x^2-54x+81) = 256

Combine like terms:

25x^2+-22x+97=256

Isolate the equation:

\displaystyle 25x^2 - 22x -159=0

We can use the quadratic formula:

\displaystyle x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

In this case, <em>a</em> = 25, <em>b</em> = -22, and <em>c</em> = -159. Substitute:

\displaystyle x = \frac{-(-22)\pm\sqrt{(-22)^2-4(25)(-159)}}{2(25)}

Evaluate:

\displaystyle \begin{aligned} x &= \frac{22\pm\sqrt{16384}}{50} \\ \\ &= \frac{22\pm 128}{50}\\ \\ &=\frac{11\pm 64}{25}\end{aligned}

Hence, our two solutions are:

\displaystyle x_1 = \frac{11+64}{25} = 3\text{ and } x_2 = \frac{11-64}{25} =-\frac{53}{25}

We have our two <em>x-</em>coordinates.

To find the <em>y-</em>coordinates, we can simply substitute it into the linear equation and evaluate. Thus:

\displaystyle y_1 = -\frac{3}{4}(3)+\frac{1}{4} = -2

And:

\displaystyle y _2 = -\frac{3}{4}\left(-\frac{53}{25}\right) +\frac{1}{4} = \frac{46}{25}

Thus, our two intersection points are:

\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)

6 0
2 years ago
PLS HELP ASAP. QUESTION IN PICTURE
Anuta_ua [19.1K]

Answer: 50 degrees

Step-by-step explanation:

This is actually quite simple using the exterior angle theory

"The exterior angle theorem states that the measure of an exterior angle is equal to the sum of the measures of the two remote interior angles of the triangle"

In this case the exterior angle is 120 degrees, basically what the theorem states is that it the angle that you see outside the triangle equals the angle measurements of the 2 angles opposite of it, so just create an equation because you know 2 of the variables

120=70+x

120-70=x

Angle x = 50 degrees

4 0
2 years ago
Study the following frequency distribution table.
m_a_m_a [10]

Answer:

Option C is correct.

f = 2

Step-by-step explanation:

The mean is the sum of variables divided by the number of variables

Mean = (Σfx)/(Σf)

xi | 15 | 17 | 20 | 30 | 10 + f

fi | 4 | 4 | 6 | 5 | 6

Σfx = (15×4) + (17×4) + (20×6) + (30×5) + [(10+f)×6] = 60 + 68 + 120 + 150 + 60 + 6f = (458 + 6f)

Σf = 4 + 4 + 6 + 5 + 6 = 25

Mean = 18.8

18.8 = (458+6f) ÷ 25

458 + 6f = 25 × 18.8 = 470

6f = 470 - 458 = 12

f = (12/6) = 2

Hope this Helps!!!

6 0
2 years ago
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