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1 year ago

Determine the vertical asymptotes for the reciprocal of this function f(x)=x^2 + 3x -28

Mathematics

1 answer:

Gennadij [26K]1 year ago

7 0

Answer:

x = -7 and x = 4.

Step-by-step explanation:

f(x) = x^2 + 3x - 28

= (x + 7)(x - 4).

The reciprocal of f(x) can be written as

1 / (x + 7)(x - 4).

When the denominator is zero we have vertical asymptotes

so they are x = -7 and x = 4.

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