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denis23 [38]
2 years ago
13

Algebra 2 help needed urgent !!!

Mathematics
1 answer:
cluponka [151]2 years ago
8 0

Answer:

  11, 7, 3, -1, -5

Step-by-step explanation:

The dependent variable y is often used interchangeably with the function value f(x). That is, we can usually presume that ...

  y = f(x)

__

<h3>evaluate the function</h3>

To find f(x), put the value of x everywhere x appears in the function definition, and do the arithmetic. A calculator or spreadsheet can relieve some of the boredom of repetition. Here are a couple of examples.

  f(-2) = -4(-2) +3 = 8 +3 = 11

  f(-1) = -4(-1) +3 = 4 +3 = 7

<h3>time saver</h3>

You may notice that each increase of 1 in the value of x causes a decrease of 4 in the value of y. That means we can simply subtract 4 from the previous value of y to find the next one:

  \begin{array}{|c|c|}\cline{1-2}x&y\\\cline{1-2}-2&11\\\cline{1-2}-1&7\\\cline{1-2}0&3\\\cline{1-2}1&-1\\\cline{1-2}2&-5\\\cline{1-2}\end{array}

__

Attached is an example of this table being filled by a calculator.

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Find the points on the ellipse 4x2 + y2 = 4 that are farthest away from the point (−1, 0).
Hitman42 [59]
<span>The two points that are most distant from (-1,0) are exactly (1/3, 4sqrt(2)/3) and (1/3, -4sqrt(2)/3) approximately (0.3333333, 1.885618) and (0.3333333, -1.885618) Rewriting to express Y as a function of X, we get 4x^2 + y^2 = 4 y^2 = 4 - 4x^2 y = +/- sqrt(4 - 4x^2) So that indicates that the range of values for X is -1 to 1. Also the range of values for Y is from -2 to 2. Additionally, the ellipse is centered upon the origin and is symmetrical to both the X and Y axis. So let's just look at the positive Y values and upon finding the maximum distance, simply reflect that point across the X axis. So y = sqrt(4-4x^2) distance is sqrt((x + 1)^2 + sqrt(4-4x^2)^2) =sqrt(x^2 + 2x + 1 + 4 - 4x^2) =sqrt(-3x^2 + 2x + 5) And to simplify things, the maximum distance will also have the maximum squared distance, so square the equation, giving -3x^2 + 2x + 5 Now the maximum will happen where the first derivative is equal to 0, so calculate the first derivative. d = -3x^2 + 2x + 5 d' = -6x + 2 And set d' to 0 and solve for x, so 0 = -6x + 2 -2 = -6x 1/3 = x So the furthest point will be where X = 1/3. Calculate those points using (1) above. y = +/- sqrt(4 - 4x^2) y = +/- sqrt(4 - 4(1/3)^2) y = +/- sqrt(4 - 4(1/9)) y = +/- sqrt(4 - 4/9) y = +/- sqrt(3 5/9) y = +/- sqrt(32)/sqrt(9) y = +/- 4sqrt(2)/3 y is approximately +/- 1.885618</span>
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4 years ago
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You are at a home improvement store to purchase a freezer. There is currently a sale on appliances for 15% off. The freezer you
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4 years ago
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Andreyy89

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3 years ago
Solve for x.<br> 5 = 3x - 3
BaLLatris [955]

Answer:

x = 8/3

Step-by-step explanation:

Step 1: Write equation

5 = 3x - 3

Step 2: Solve for <em>x</em>

  1. Add 3 to both sides: 8 = 3x
  2. Divide both sides by 3: 8/3 = x
  3. Rewrite: x = 8/3

Step 3: Check

<em>Plug in x to verify it's a solution.</em>

5 = 3(8/3) - 3

5 = 8 - 3

5 = 5

7 0
4 years ago
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