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Amiraneli [1.4K]
3 years ago
6

Express the complex number in trigonometric form. 5 - 5i

Mathematics
2 answers:
bazaltina [42]3 years ago
6 0

●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

               Hi my lil bunny!

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

Lets do this step by step.

This is the trigonometric form of a complex number where |z| is the modulus and 0 is the angle created on the complex plane.

z = a + bi = |z| (cos ( 0 ) + I sin (0))

The modulus of a complex number is the distance from the origin on the complex plane.

|z| = \sqrt{a^2 + b^2} where z = a + bi

Substitute the actual values of a = -5 and b = -5.

|z| = \sqrt{(-5) ^2 + (-5) ^2}

Now Find |z| .

Raise - 5 to the power of 2.

|z| = \sqrt{25 + (-5) ^2}

Raise - 5 to the power of 2.

|z| = \sqrt{25 + 25}

Add 25 and 25.

|z| = \sqrt{50}

Rewrite 50 as 5^2 . 2 .

|z| = 5\sqrt{2}

Pull terms out from under the radical.

|z| = 5\sqrt{2}

The angle of the point on the complex plane is the inverse tangent of the complex portion over the real portion.

0 = arctan (\frac{-5}{-5} )

Since inverse tangent of  \frac{-5}{-5}  produces an angle in the third quadrant, the value of the angle is \frac{5\pi }{4} .

0 = \frac{5\pi }{4}

Substitute the values of 0 = \frac{5\pi }{4} and |z| = 5\sqrt{2} .

5\sqrt{2} ( cos( \frac{5\pi}{4})  + i sin (\frac{5\pi}{4}))

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

Hope this helped you.

Could you maybe give brainliest..?

❀*May*❀

kolbaska11 [484]3 years ago
6 0

Answer:

five square root two times the quantity cosine of five pi divided by four plus i times sine of five pi divided by four

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Ne4ueva [31]

Answer:

The first 5 terms are;

-2, 2, 13,38 and 91

Step-by-step explanation:

Here, we want to write the first 5 terms of the sequence.

We already have the first term as 1

Now, we need the 2nd term

Putting two in place of n, we have ;

2f(1) + 3n

= 2(-2) + 3(2) = -4 + 6 = 2

For the 3rd term, put 3 in place of n

2f(2) + 3(3)

sine f(2) = 2, we have

2(2) + 9 = 4+ 9 = 13

For the fourth term, put 4 in place of n, we have

2f(3) + 3(4)

since f(3) = 13

we have; 2(13) + 12 = 26 + 12 = 38

For the 5th term, put 5 in place of n, we have

2f(4) + 3(5)

since f(4) = 38, we have

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6 0
3 years ago
Let X be the number of accidents per week at the Hillsborough Street roundabout by the NCSU Bell Tower. Assume X varies with mea
Eduardwww [97]

Answer:

1) 0.1587 = 15.15% probability that x is less than 2

2) 7.64% probability that there are fewer than 100 accidents at the roundabout in a year

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the Central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 2.2, \sigma = 1.4

1)

Here we have \mu = 2.2, s = \frac{1.4}{\sqrt{52}} = 0.194

What is the probability that x is less than 2?

This is the pvalue of Z when X = 2.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{2 - 2.2}{0.194}

Z = -1.03

Z = -1.03 has a pvalue of 0.1515

0.1587 = 15.15% probability that x is less than 2

2)

100/52 = 1.9231

This is the pvalue of Z when X = 1.9231

Z = \frac{X - \mu}{s}

Z = \frac{1.9231 - 2.2}{0.194}

Z = -1.43

Z = -1.43 has a pvalue of 0.0764

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3 years ago
At a school number of boys: number of girls= 11:9
vredina [299]

составим уравнение
11х=9х+124
2х=124
х=62

проверим ответ
682=558+124

тогда, общее количество детей

682+558=1240

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